The right system of equations to describe the situation would
be on the form:
x1 = 8000 + y1*t
and
x2 = 8000 + y2*t
where x1 and x2 represents the total money of Imogene and her
friend respectively at the end of t years.
Now for the value of amount earned, y1 and y2:
y1=8000*0.08
y2=2000*√(t-2)
<span> </span>
Circunference=diameter time pi
aprox pi to 3.14
circunference=200.332
subsitue
200.332=diameter time s3.14
divide both sides by 3.14
63.8=diameter
answer is 63.8 units
I think the answer might be B. $4,754.60 but I'm not sure. Sorry
Answer:
![sin(t)=\frac{\sqrt{99}}{10}](https://tex.z-dn.net/?f=sin%28t%29%3D%5Cfrac%7B%5Csqrt%7B99%7D%7D%7B10%7D)
Step-by-step explanation:
Remember that
If angle t belong to the First Quadrant
then
The value of sin(t) and cos(t) are positive values
we know that
---> by trigonometric identity
we have
![cos(t)=0.1=\frac{1}{10}](https://tex.z-dn.net/?f=cos%28t%29%3D0.1%3D%5Cfrac%7B1%7D%7B10%7D)
substitute
![sin^2(t)+(\frac{1}{10})^2=1](https://tex.z-dn.net/?f=sin%5E2%28t%29%2B%28%5Cfrac%7B1%7D%7B10%7D%29%5E2%3D1)
![sin^2(t)+\frac{1}{100}=1](https://tex.z-dn.net/?f=sin%5E2%28t%29%2B%5Cfrac%7B1%7D%7B100%7D%3D1)
![sin^2(t)=1-\frac{1}{100}](https://tex.z-dn.net/?f=sin%5E2%28t%29%3D1-%5Cfrac%7B1%7D%7B100%7D)
![sin^2(t)=\frac{99}{100}](https://tex.z-dn.net/?f=sin%5E2%28t%29%3D%5Cfrac%7B99%7D%7B100%7D)
![sin(t)=\frac{\sqrt{99}}{10}](https://tex.z-dn.net/?f=sin%28t%29%3D%5Cfrac%7B%5Csqrt%7B99%7D%7D%7B10%7D)
Answer:
upon graphing, it is linear
Step-by-step explanation:
you could set up an x-y table or you could graph it
if you graph it you'll see it's linear with a y-intercept of -2 and a slope of 9
all linear equations are functions except for vertical lines