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Flura [38]
3 years ago
5

Paul is driving his car and he changes his velocity from 5 m/s to 15 m/s in 2 seconds. Is

Biology
2 answers:
leonid [27]3 years ago
6 0

Answer:

positive acceleration

Explanation:

hope this helps!!!

charle [14.2K]3 years ago
5 0

Answer:

this is an example of a positive acceleration because Paul is speeding up not slowing down

Explanation:

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Which of these is an example of a haploid cell?
zavuch27 [327]

Answer:

Gametes

Explanation:

Gametes are an example of a haploid cell and are produced as a result of meiosis.

7 0
3 years ago
An allele that expresses itself in a heterozygote is a(n)
Triss [41]
The answer is C. Dominant allele
4 0
3 years ago
7. Based on their shape, how would you classify these Fungi? (Which Division do they fit?) I would classify them as sac fungi
swat32

Answer:

To match the features and characteristics.

Explanation:

We can classify these Fungi on the basis of their features and characteristics that resembles to the different divisions of fungi. Fungi are classified in four divisions i.e. the Chytridiomycota (chytrids), Zygomycota (bread molds), Ascomycota (yeasts and sac fungi), and the Basidiomycota (club fungi). There are specific characteristics of every division of fungi so we have to match the physical features of unknown fungi with these divisions and classify them.

5 0
2 years ago
WHAT ARE THE CHARACTERISTICS OF EUKARYOTIC CELLS?
Shalnov [3]

Answer:

Like a prokaryotic cell, a eukaryotic cell has a plasma membrane, cytoplasm, and ribosomes. However, unlike prokaryotic cells, eukaryotic cells have: a membrane-bound nucleus. numerous membrane-bound organelles

Explanation:

6 0
3 years ago
Read 2 more answers
A farmer is experimenting with pea plants. If the farmer crosses two pea plants with round and yellow peas (genotype RrYy) how m
seropon [69]

Answer:

The genotype of both parents is RrYy.

The possible types of gametes would be RY, Ry, rY, and ry.

The cross would produce offspring that can have one out of four types of phenotypes:

  • Round and yellow seeds (1 RRYY+ 2 RrYY +2 RRYy + 4 RrYy) = 9/16
  • Wrinkled and yellow seeds (3 rrYy) = 3/16
  • Round and green seeds (1 RRyy + 2 Rryy) = 3/16
  • Wrinkled and green seeds (rryy) = 1/16

Thus, one out of 16 offspring would have wrinkled and green seeds.

4 0
3 years ago
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