$\left(\frac{3}{7}x+9\right)-\left(\frac{2}{7}x-3\right)\\\\=\frac{3}{7}x+9-\frac{2}{7}x-(-3)\\\\=\frac{3}{7}x+9-\frac{2}{7}x+3\\\\=(\frac{3}{7}x-\frac{2}{7}x)+(9+3)\\\\=\frac{3-2}{7}x+12\\\\=\boxed{\frac{1}{7}x+12}$

4 0

3 years ago

What is the answer to - 1/3 (x+6)=0

Sauron [17]

$(-\frac{1}{3})(x+6)=0\\\\\frac{1}{3}(x+6)*3=0*3\\\\-1(x+6)=0\\\\-(x+6)*-1=0*-1\\\\x+6=0\\\\x=-6$

3 0

3 years ago

Read 2 more answers

Evaluate 4c + 8 when c = 2

Wittaler [7]

Answer:

Step-by-step explanation:

4c + 8

Replace 'c' with 2 and evaluate:

4(2) + 8

8 + 8

Hope this helps.

8 0

3 years ago

Read 2 more answers

Write an expression that gives the requested sum. the sum of the first 18 terms of the geometric sequence with first term 3 and

alina1380 [7]

I got 786432 when I use a(r^n-1)/(r-1)

8 0

3 years ago