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vaieri [72.5K]
3 years ago
10

Evaluate 4c + 8 when c = 2

Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

16

Step-by-step explanation:

4c + 8

Replace 'c' with 2 and evaluate:

4(2) + 8

8 + 8

16

Hope this helps.

Masja [62]3 years ago
3 0

Answer:

# 16 Answer

4c+8

c=2

4×2 +8

8+8

=16

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The quotient of n and 7 is 39
Harrizon [31]
N = 273

273 / 7 = 39
Dividend / divisor = quotient


Work Backwards:

n/7 = 39
n = 39 X 7
n = 273
8 0
3 years ago
Use a graphing utility to graph the function and the damping factor of the function in the same viewing window.
Bas_tet [7]

Answer:

The function touches the damping factor

at x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

The x-intercept of f(x) is

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Step-by-step explanation:

Given function is f(x)=e^{-3x} sin(x) and damping factor as y=e^{-3x} and y=(-1)e^{-3x}

To find when function touches the damping factor:

For f(x)=e^{-3x} sin(x) and y=e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=e^{-3x}

sin(x)=1

x=\frac{(4n-3)\pi}{2}

For f(x)=e^{-3x} sin(x) and y=(-1)e^{-3x}

Equating the both the equation,

e^{-3x} sin(x)=(-1)e^{-3x}

sin(x)=(-1)

x=\frac{(4n-1)\pi}{2}

Therefore, The function touches the damping factor x=\frac{(4n-3)\pi}{2} and x=\frac{(4n-1)\pi}{2}

To find x-intercept of f(x):

For x-intercept, y=0

f(x)=e^{-3x} sin(x)

y=e^{-3x} sin(x)

e^{-3x} sin(x)=0

Hence, e^{-3x} is always greater than zero.

Therefore,sin(x)=0

x=n\pi

Thus,

The x-intercept of f(x) is at x=n\pi

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Answer:

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Stolb23 [73]

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Step-by-step explanation:

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