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3 years ago

Help please????????????????

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

Answer:

the answer is 289.38

Step-by-step explanation:

the equation for area of circle is pi r ^2

so plug them in 3.14(9.6^2)=

3.14*92.16= approx 289.38

raketka [301]3 years ago

4 0

Answer: 289.38

Step-by-step explanation: the formula of finding the area of a circle is pi times radius squared. The cheesy joke to help you remember that is, pi r2 (pie are squared) , no pie are round.

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Which are solutions to 3sin^2 θ - 2sin θ = 0, 90°≤θ≤90°

jeka57 [31]

Answer:

The solutions of the equation are -41.8° , 0.0° , 41.8°

Step-by-step explanation:

∵ 3 sin²Ф - 2 sinФ = 0 is a quadratic function

∵ The domain of the function is -90° ≤ Ф ≤ 90°

- Lets take sinФ as a common factor

∴ sinФ (3 sinФ - 2) = 0

- Two terms multiplied by each other = 0

∴ One of them must be equal zero

∴ sinФ = 0 or 3 sinФ - 2 = 0

- If sinФ = 0 ⇒ Ф = 0.0°

- If 3 sinФ - 2 = 0 ⇒ 3 sinФ = 2 ⇒ sin Ф = 2/3

∵ sinФ 2/3

∴ Ф = 41.8° ⇒ Ф ≤ 90° (in first quadrant)

∵ -90° ≤ Ф ≤ 90°

∴ Ф = -41.8° ⇒ Ф ≥ -90° (in fourth quadrant)

∴ The solutions of the equation are -41.8° , 0.0° , 41.8°

4 0

4 years ago

Which graph represents —3x+ 5y < 15?

Svetllana [295]

The top graph
hope this help

8 0

4 years ago

Read 2 more answers

Helps to this answering please math

Pepsi [2]

1 million is the answer

6 0

3 years ago

Heya!

nataly862011 [7]

Answer:

$m\angle QSN=65^\circ$

Step-by-step explanation:

In the given figure, PQRS is a rhombus and SRM is an equilateral triangle.

We are also given that SN⊥RM and that ∠PRS = 55°.

And we want to find the measure of ∠QSN.

Remember that since PQRS is a rhombus, the angles formed by its diagonals are right angles. Let the intersection point of the diagonals be K. Therefore:

$m\angle RKS=90^\circ$