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2 years ago

Help please????????????????

Mathematics

2 answers:

navik [9.2K]2 years ago

6 0

Answer:

the answer is 289.38

Step-by-step explanation:

the equation for area of circle is pi r ^2

so plug them in 3.14(9.6^2)=

3.14*92.16= approx 289.38

raketka [301]2 years ago

4 0

Answer: 289.38

Step-by-step explanation: the formula of finding the area of a circle is pi times radius squared. The cheesy joke to help you remember that is, pi r2 (pie are squared) , no pie are round.

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1. Zoey took a taxi from her house to the airport. The taxi company charged a pick-up fee of $1.20 plus $3.25 per mile. The tota

RoseWind [281]

equation:3.25x+1.2=40.2

ansrew:x=12

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3 years ago

(Giving Branliest)

REY [17]

Answer:

106.68 cm

Step-by-step explanation:

Change ft to inches

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2 years ago

Read 2 more answers

Which table represents a linear function?

Viktor [21]

Answer:

table C represents a linear function.

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2 years ago

A bag contains Red, Green and Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.35 and t

Eddi Din [679]

Answer:

P(Yellow)=0.25
P(Not Red)=0.65

Step-by-step explanation:

P(Red)=0.35

P(Green)=0.4

(a)Since there are three colours inside the bag

P(Red)+P(Green)+P(Yellow)=1

0.35+0.4+P(Yellow)=1

P(Yellow)=1-(0.35+0.4)

P(Yellow)=0.25

(b) In probability, the sum of an event and its complement is 1.

Therefore:

P(Red)+P(Not Red)=1

0.35+P(Not Red)=1

P(Not Red)=1-0.35

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3 0

2 years ago

A popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags

ELEN [110]

Answer:

Step-by-step explanation:

Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.

i.e. Sample mean = 1040 and

Sample std dev s = 25 gm

Sample size n = 100

Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

$\bar X = N(1040,25)$

Normal curve would be with mean 1040 and std deviatin 25

b) P(X>1115)

= 1-0.9987

=0.0013

i.e. 0.13% would receive a bag that had a weight greater than 1115 grams

8 0

3 years ago