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Salsk061 [2.6K]
3 years ago
7

If the radius of a circle is perpendicular to a chord, then

Mathematics
1 answer:
Serhud [2]3 years ago
5 0

If the radius of a circle is perpendicular to a chord, 1. the radius bisects the chord and 2. right angles are created at the point where they meet.

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Last year, 50 students attended the winter carnival. This year, 60 students attended the carnival. Which statement below correct
SVETLANKA909090 [29]

Answer: 20% increase

Step-by-step explanation:

change/ original number

(60 - 50 / 50) x 100 = 20

20%

5 0
3 years ago
Read 2 more answers
There are 84 students in the glee club there are 12 more boys than girls what is the ratio of the number of girls to the number
Masja [62]
Let us denote the number of boys in the glee club with X and the number of girls with Y.There are 84 students in the glee club, which means that the following equation can be written:X+Y=84We also now that there are 12 more boys than girls, so:X=Y+12We can rewrite the first equation like:(Y+12)+Y=842Y+12=842Y=62Y=62/2=31X=31+12=43So, the ratio of the number of girls to the number of boys is: Y/X=31/43
Read more on Brainly.com - brainly.com/question/4711779#readmore
5 0
3 years ago
Can someone please help me ASAP :)
jeyben [28]
Did this a couple years ago, im kinda lost xD . sorry
4 0
3 years ago
1+secA/sec A = sin^2 A / 1-cos A​
Fofino [41]

Answer:  see proof below

<u>Step-by-step explanation:</u>

\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}

\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}

\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}

\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}

\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}

\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark

3 0
4 years ago
Graph ​y&lt;1−3x​. .......................... . .
Mkey [24]

Answer:

algobn tu jale

Step-by-step explanation:

yo digo q C es la megor opceon

4 0
3 years ago
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