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2 years ago

Find out how far the ball will travel, thanks. Will give brainliest.

Mathematics

2 answers:

Dmitriy789 [7]2 years ago

6 0

Answer:

127ft

Step-by-step explaination:

Ezzz

kirill115 [55]2 years ago

5 0

Answer:

127 ft

Step-by-step explanation:

split the square diagonally and use the pythagorean theorem

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Can someone please help me I don’t understand this. I keep getting it wrong

kicyunya [14]

Answer:

K- (-8, -2)

L- (2, -2)

J- (-8, -5)

M- (2, -5)

Step-by-step explanation:

Vertices refer to the points where the lines connect, or corners. In this problem they're represented by K, L, J, and M.

The current coordinates are-

K- (-8, -4)

L- (2, -4)

J- (-8, -7)

M- (2, -7)

Since the Y coordinate refers to vertical distance and the X coordinate refers to horizontal distance, translating them two units up would involve adding positive two to each y coordinate.

Therefore the new coordinates would be

K- (-8, -2)

L- (2, -2)

J- (-8, -5)

M- (2, -5)

Hope this was helpful! Sorry if I messed up askdjasjk

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4 years ago

Solve for n <br> 3n - 7 = 6n - 2n

Vika [28.1K]

Answer: n=-7

Step-by-step explanation:

3n-7=6n-2n

3n-7=4n

-7=n

n=-7

6 0

3 years ago

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What is 7.2km/h in m/s?

lukranit [14]

Answer: 2 meters/ seconds

Step-by-step explanation

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3 years ago

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

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2 years ago

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Consider the relationship below, given . Which of the following best explains how this relationship and the value of sin can be

vova2212 [387]

Answer:

The values of sin θ and cos θ represent the legs of a right triangle with a hypotenuse of 1; therefore, solving for cos θ finds the unknown leg, and then all other trigonometric values can be found.

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3 years ago

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