Find an equation for a line that passes through points -4,3 and 6,5
2 answers:
First you would want to find the slope. The equation for slope is y2-y1/x2-x1. So the slope would be 5-3/ 6-(-4). Two negatives make a positive so it would be 5-3/6+4 or 2/10 which can be simplified to 1/2. Next you used the point slope form equation. y-y1 =m(x-x1) m is the slope we just found: 1/2 the equation would be = y-3=1/2(x-(-4)) two negatives make a positive so the equation would now be y-3=1/2(x+4) You then distribute the x to what is in the parenthesis y-3=1/2x+2 then add the 3 to both sides you’re equation should be y=1/2+5
Answer: Find the equation of the line that passes through the points (-6,2) and (-5,3). Write your answer in standrard form. Answer by fractalier(6550) ...
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