Since the details are not available, we have provided an overview of William's total fixed and variable expenses for the first year of college.
<h3>What are college costs?</h3>
There are five categories of college costs.
These college costs include tuition, room and board, books and supplies, personal expenses, and transportation.
Some of the college costs like tuition and room and board may be relatively fixed.
This leaves expenses like books and suppliers, personal expenses, and transportation relatively variable.
Thus, William needs to control his variable college costs so that they do not exceed the student loan.
Learn more about college costs at brainly.com/question/11650418
#SPJ1
Coming from a 6th grader but I hope this is right!
Polynomials of degree greater than 2 can have more than one max or min value. The largest possible number of minimum or maximum points is one less than the degree of the polynomial. The following examples illustrate several possibilities.
since the degree is 4
number of possible extreme values = 4 -1 = 3
Answer:
1 cm^2 = 100 mm^2
9 cm^2 = 900 mm^2
5.2 cm^2 = 520 mm^2
1 dm^2 = 100 cm^2
17 dm^2 = 1700 cm^2
4.3 dm^2 = 430 cm^2
1 m^2 = 10000 cm^2
7 m^2 = 70000 cm^2
2.5 m^2 = 25000 cm^2
1 km^2 = 1000000 m^2
50 km^2 = 50000000 m^2
8.5 km^2 = 8500000 m^2
Step-by-step explanation:
1 cm = 10 mm
1 
= 10×10 
= 100
9 = 9×100 = 900
5.2 = 5.20×100 = 520
1 dm = 10 cm
1 
= 10×10 = 100
17 = 17× 100 = 1700
4.3 = 4.3 × 100 = 430
1 m = 100 cm
1 
= 100×100 = 10000
7 = 7×10000 = 70000
2.5 = 2.5×10000 = 25000
1 km = 1000 m
1 
= 1000×1000 = 1000000
50 = 50×1000000 = 50000000
8.5 = 8.5×1000000 = 8500000
Answer:
The width of rectangle w = 4 units
Step-by-step explanation:
We are given:
Width of rectangle = w
Length of rectangle = w+ 4
Area of rectangle = 32 units
We need to find width of the rectangle
The formula used is: 
Putting values and finding width of rectangle
We need to solve this quadratic equation to find width (w)
We will use factorisation and break the middle term.
Since width of rectangle can't be negative, so rejecting w=-8
Therefore, the width of rectangle w = 4 units
