Solve the system using substitution.
X + 5y = 0
3y + 2x = -21
([?], 1)
1 answer:
Answer:
(-15, 3)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
x + 5y = 0
3y + 2x = -21
<u>Step 2: Rewrite Systems</u>
x + 5y = 0
- Subtract 5y on both sides: x = -5y
<u>Step 3: Redefine Systems</u>
x = -5y
3y + 2x = -21
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 3y + 2(-5y) = -21
- Multiply: 3y - 10y = -21
- Combine like terms: -7y = -21
- Isolate <em>y</em>: y = 3
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define equation: x + 5y = 0
- Substitute in <em>y</em>: x + 5(3) = 0
- Multiply: x + 15 = 0
- Isolate <em>x</em>: x = -15
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