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3 years ago

Solve the system using substitution. X + 5y = 0 3y + 2x = -21 ([?], 1)

Mathematics

1 answer:

Tpy6a [65]3 years ago

8 0

Answer:

(-15, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x + 5y = 0

3y + 2x = -21

Step 2: Rewrite Systems

x + 5y = 0

Subtract 5y on both sides: x = -5y

Step 3: Redefine Systems

x = -5y

3y + 2x = -21

Step 4: Solve for y

Substitution

Substitute in x: 3y + 2(-5y) = -21
Multiply: 3y - 10y = -21
Combine like terms: -7y = -21
Isolate y: y = 3

Step 5: Solve for x

Define equation: x + 5y = 0
Substitute in y: x + 5(3) = 0
Multiply: x + 15 = 0
Isolate x: x = -15

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Answer:

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Step-by-step explanation:

The two triangles in the diagram are:

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First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

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Solving for triangle ABC

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Hence,

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