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malfutka [58]
3 years ago
10

During a thunderstorm, 600 millimeters of rain fell in 30 minutes. How fast did the rain fall, in millimeters per minute?

Mathematics
2 answers:
madreJ [45]3 years ago
5 0
20 milliliters per minute
N76 [4]3 years ago
4 0
The rain fell 20 millimeters per minute.

Explanation:

To find the answer, we must divide the amount of rain by the number of minutes it took to fall.

600 divided by 30 = 20 millimeters.
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Answer:

The average U.S. citizen throws away about 133.8 pounds of garbage a month.

Step-by-step explanation:

First take the total amount of trash thrown away in a year (1,606), and divide it by the number of months in a year (12).

1,606 / 12 = 133.833333

You would get 133.833333 and would round it to the nearest tenth and get 133.8.

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Applying the Third Corollary to the Inscribed Angles Theorem A circle is shown. Points A, B, C, and D are on the circle. Lines c
Marat540 [252]

Answer:

  • ∠B = 110°
  • ∠D = 70°

Step-by-step explanation:

Opposite angles in an inscribed quadrilateral are supplementary, so ...

  ∠B +∠D = 180°

  (3x -4) +(2x -6) = 180

  5x = 190 . . . . . . . . . . . add 10, collect terms

  x = 38 . . . . . . . . . . . . . divide by 5

  ∠D = 2(38) -6 = 70

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Complete the table shown to the right for the population growth model for a certain country.
marta [7]

The size of the population increases when the growth rate is positive and

decreases for a negative growth rate.

The completed table is presented as follows;

\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \  K \\40.5&20.9&-2.255\%\end{array}\right]

Reasons:

The table is presented as follows;

\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \  K \\40.5&20.9&\end{array}\right]

The population in growth rate is given by the following formula;

P = a·(1 + r)ˣ

Where;

a = The initial population in 2003 = 40.5 million

P = The population in 2029 = 20.9 million

x = The number of years = 2029 - 2003 = 26

Therefore;

20.9 = 40.5 × (1 + r)²⁹

\left (1 + r\right)^{29} = \dfrac{20.9}{40.5}

r = \left(\dfrac{20.9}{40.5} \right)^{\dfrac{1}{29} } - 1 \approx  -0.02255

The population growth rate is r ≈ -0.02255 = -2.255 %

The completed table is therefore;

\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \  K \\40.5&20.9&-2.255\%\end{array}\right]

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