Answer:
The probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Step-by-step explanation:
Let the random variable <em>X</em> denote the water depths.
As the variable water depths is continuous variable, the random variable <em>X</em> follows a continuous Uniform distribution with parameters <em>a</em> = 2.00 m and <em>b</em> = 7.00 m.
The probability density function of <em>X</em> is:
Compute the probability that a randomly selected depth is between 2.25 m and 5.00 m as follows:
![=\frac{1}{5.00}\int\limits^{5.00}_{2.25} {1} \, dx\\\\=0.20\times [x]^{5.00}_{2.25} \\\\=0.20\times (5.00-2.25)\\\\=0.55](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B5.00%7D%5Cint%5Climits%5E%7B5.00%7D_%7B2.25%7D%20%7B1%7D%20%5C%2C%20dx%5C%5C%5C%5C%3D0.20%5Ctimes%20%5Bx%5D%5E%7B5.00%7D_%7B2.25%7D%20%5C%5C%5C%5C%3D0.20%5Ctimes%20%285.00-2.25%29%5C%5C%5C%5C%3D0.55)
Thus, the probability that a randomly selected depth is between 2.25 m and 5.00 m is 0.55.
Answer:
number one is 3 Step-by-step explanation:
number 2
the answer is 2
number 3
answer is 42
number 4 answer is 15
Radius ^2 * pi = 1 pizza * 2 = area of 2 pizzas = 307.876 in ^2
Answer : The value of x and y is 8 and 10 respectively.
Step-by-step explanation :
As we known that if two parallel lines are cut by a transversal line then consecutive interior angles are supplementary.
From the given figure we conclude that:
...........(1)
............(2)
...........(3)
...........(4)
Now we adding equation 2 and 4, we get the value of x.
Now we are putting the value of x in 4, we get the value of y.
Therefore, the value of x and y is 8 and 10 respectively.
Because like terms you add or subtract together to make it easier to do the problem. just like you do with whole numbers. you add an subtract to make the answer simpler.
