9514 1404 393
Answer:
$44,935
Step-by-step explanation:
The amount due will be ...
A = P(1 +rt) . . . . principal P at annual rate r for t years
__
3 months is 3/12 = 1/4 years, so the amount is ...
A = $44,000(1 +0.085×1/4) = $44,935 . . . amount paid back
Answer:
Step-by-step explanation:
Answer:
$32.70
Step-by-step explanation:
9% of 30 is 2.70 so you add it together and get the answer
Answer:

Step-by-step explanation:
We have to simplify the trigonometric expression 
Let us multiply the numerator and denominator by 

In the denominator apply the formula for difference of squares

Thus, the denominator will become

Thus, the expression is

Using the relation 

We can rewrite this expression as

Finally, the simplified expression is
