No because (-7, 3) is like (x, y)
Plug and chug [what I call it] into the equation
(3) - 4(-7) < 5
3- (-28)<5
31<5 <—— this is not true so it would be galse
Answer:
The quotient of any two numbers can be written as:
A/B
such that:
A, B ∈ {R}
Where {R} is the set of all real numbers.
But we also have the restriction that the denominator, B in this case, must be different than zero.
So we can define the set:
{R \ {0}}
As the set of all the real numbers minus the element 0.
So in this set we do not have the number zero, so now we can write our expression as:
A/B
A ∈ {R}, B ∈ {R \ {0}}
K.E=0.5mv^2
GPE=mgh
The child has both K.E and GPE
g is taken as 9.81
Answer:
x^15
Step-by-step explanation:
Recall these rules of exponents:
(a^m)^n = a^mn
a^m • a^n = a^(m + n)
(x^6)² • x³ = x^(2 • 6) • x³ = x^12 • x³ = x^(12 + 3) = x^15
Answer:
a number
Step-by-step explanation:
this was asked in april so i rly think you need an answer anymore
