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Nata [24]
3 years ago
7

What’s the median for 55, 42, 78, 99, 69, 83, 74, 83, 97

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
The median of this is 78
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Work out 10.3 % of 853.93 km Give your answer rounded to 2 DP.
Vilka [71]

Answer: 87.95

Step-by-step explanation: 10.3% of 853.93

10.3%= 0.103

So you would do 0.103 times 853.93=87.95479 round that to 2 Dp. You get 87.95

7 0
3 years ago
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
A circular lawn has a row of bricks around the edge. The diameter of the lawn is about 40 feet.
Murrr4er [49]

Answer:

1250

Step-by-step explanation:

please tell me if I am incorrect

7 0
3 years ago
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If g(x)= x^2 -x, find g(-1)+4
NikAS [45]

Answer:

-g + 4

Step-by-step explanation:

6 0
2 years ago
Can anyone help? I’ll give Brainly + 15 pts
Brilliant_brown [7]

Answer:

14 inches.....................

8 0
3 years ago
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