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Nata [24]
3 years ago
7

What’s the median for 55, 42, 78, 99, 69, 83, 74, 83, 97

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
8 0
The median of this is 78
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PLEASE HELP<br><br> Which of the following is the inverse of f(x)=3-x/5
BabaBlast [244]

Answer:

f^-1(x) = 3 - 5x, second option

Step-by-step explanation:

To determine the inverse simply interchange the variables and solve for y;

f(x) = 3 - x / 5 -> Interchange the variables

x = 3 - y/5 -> Multiply either side by 5

5x = 3 - y -> Subtract three from either side

- y = 5x - 3 -> Divide either side by - 1

y = - 5x + 3

Your solution is f^-1(x) = 3 - 5x

8 0
3 years ago
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

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Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
WILL GIVE BRAINLIEST! PLEASE HELP I'm doing an exam!! A photograph is reduced by a scale factor of 3/4. If the original length o
Harlamova29_29 [7]
13.5 inches, because if you add 4.5x4 or 9x2 it equals 18, then you just subtract 4.5 from 18 and it’s 13.5
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3 years ago
WIL GIVE BRAINLIEST ANSWER! HELP ASAP!
Evgesh-ka [11]

Answer:

Multiply the divisor and dividend by 100.

Step-by-step explanation:

The first step is to eliminate decimal points in both divisor and dividend. Since to convert 0.15 to a whole number you multiply by 100 then it means both the divisor and dividend should be multiplied by 100. So that we shall have 4860/15=324

6 0
3 years ago
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Solve any method: 9x^2+9x=4??
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Subtract 4 from both sides, solve using quadratic formula
ax^2+bx+c
(-b(+or-) Square Root of b^2 - 4ac)/2a

9x^2+9x-4=0
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Solve^
6 0
3 years ago
Read 2 more answers
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