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2 years ago

The factorization of a (x + y + z) + b(x + y + z) + c(x + y + z) is

Mathematics

2 answers:

levacccp [35]2 years ago

7 0

Answer:

(a+b+c) (x+y+z)

Step-by-step explanation:

hope this helps to uh

Reptile [31]2 years ago

7 0

Step-by-step explanation:

x+y+z+bx+by+bz+cx+cy+cz

Take Like terms

x+bx+cx+y+by+cy+z+bz+cz

x(b+c)+y(b+c)+z(b+c)

(x+y+z)(b+c)

hope it helps

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Digiron [165]

The answer is g. 47.1

you use the formula
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3 years ago

Write and solve a proportion to answer the question. 36 is 0.9% of what number w? =0.9100

pickupchik [31]

Answer:

Step-by-step explanation:

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36 = 0.009x

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3 years ago

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Step-by-step explanation:

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2 years ago

Determine if the statement below is always, sometimes, or never true. There are 250 degrees in the sum of the interior angles of

ZanzabumX [31]

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2 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

2 years ago

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