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3 years ago

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Tiffany is planning a vacation. The hotel costs $60 per night and her flight costs $220. Tiffany has $600 dollars to spend on th

e vacation. Given her budget and the trip costs, how many nights can she spend in a hotel? Let n represent the number of nights in the hotel.
Which of the equations below best represents the situation?

Question 2 options:

600n - 220 = 60

22n + 600 = 60

60n + 600 = 220

60n + 220 = 600

1 answer:

Masteriza [31]3 years ago

6 0

Answer:

60n+220=600

Step-by-step explanation:

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3 years ago

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A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part

Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{8726}{20} = 436.3$

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

$S.D = \sqrt{\frac{75924.2}{19}} = 63.21$

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

$Mean =\displaystyle\frac{8406}{20} = 420.3$

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

$S.D = \sqrt{\frac{247636.2}{19}} = 114.16$

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

Thus. the standard deviation increased but there was no change in the interquantile range.

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3 years ago

Evaluate |x + y|, for x = 8 and y = -15.<br><br> 7<br> -7<br> 23<br> -23

natka813 [3]

Answer:

7

Step-by-step explanation:

When evaluating absolute values, a great way to remember what they do is simple. No matter the number, whether it is negative or positive, the number(s) IN THE absolute values are ALWAYS positive.

So, |x + y| is then substituted with the numbers given for the variables.

|x + y|

|8 - 15|

|-7|

7

Hope this helps!

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#A is the highest if you look at it, it says height=Constant x Width so that is your answer

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A man wishes to keep some money in savings de-

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Answer:

He needs to deposit N76800 now.

Step-by-step explanation:

The amount of money is compound interest after t years is given by:

$P(t) = P(0)(1+r)^t$

In which P(0) is the initial amount of money invested and r is the interest rate, as a decimal.

25% compound interest so that after 3 years to buy a car for N150000.

This means that:

$t = 3, P(t) = 150000, r = 0.25$ . So

$P(t) = P(0)(1+r)^t$

$P(t) = P(0)(1+0.25)^t$

$P(t) = P(0)(1.25)^t$

$150000 = P(0)(1.25)^3$

$P(0) = \frac{150000}{(1.25)^3}$

$P(0) = 76800$

He needs to deposit N76800 now.

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2 years ago