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lyudmila [28]
3 years ago
8

#5-9: Match each equation with the description of its graph below.(Plz answer! I really NEED help!!!!)

Mathematics
1 answer:
Dimas [21]3 years ago
6 0

Answer:

5)y =  \frac{7}{8}x + 1 \\ 6)y =   - 10x \\ 7)y = 2.5x - 7 \\ 8)y = 1.2x \\ 9)y =  - 5x - 8

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1-sin60÷cos60=1-Tan30÷1+Tan30
ipn [44]

Step-by-step explanation:

LHS=(1-sin60)/cos60

=(1-√3÷2)/1÷2

=2(1-√3÷2)

=2-√3

RHS=(1-tan30)/(1+tan30)

={1-(1÷√3)}/{1+(1÷√3)}

={(√3-1)/√3}/{(√3+1)/√3}

=(√3-1)/(√3+1)

={(√3-1)(√3-1)}/{(√3+1)(√3-1)}

=(3-√3-√3+1)/(3-1)

=(4-2√3)/2

=2-√3

Therefore LHS=RHS

8 0
4 years ago
Solve for x x -8 = -14
Anit [1.1K]

Answer:

-6

Step-by-step explanation:

x - 8 = -14

Add 8 to both sides of the equation

x - 8 + 8 = -14 + 8

x = -6

4 0
3 years ago
Read 2 more answers
Among the equation students taking a graduate statistics class, equation are master students and the other equation are doctoria
OleMash [197]

Answer:

a) P=0.2861

b) P=0.0954

c) P=0.3815

d) P=0.6185

Step-by-step explanation:

The question is incomplete:

<em>Among the N=16 students taking a graduate statistics class, A=10 are master students and the other N-A=6 are doctorial students. A random sample of n=5 students is going to be selected to work on a class project. Use X to denote the number of master students in the sample. Keep at least 4 decimal digits if the result has more decimal digits. </em>

<em> </em>

<em>a) The probability that exactly 4 master students are in the sample is closest to? </em>

<em> b) The probability that all 5 students in the sample are master students is closest to? </em>

<em> c) The probability that at least 4 students in the sample are master students is closest to? </em>

<em> d) The probability that at most 3 students in the sample are master students is closest to?</em>

<em />

We use a binomial distribution with n=5, with p=10/16=0.625 (proportion of master students).

a)

P(k=4)=\binom{5}{4}p^4q^1=5*0.625^4*0.375=5*0.1526*0.3750\\\\P(k=4)=0.2861

b)

P(k=5)=\binom{5}{5}p^5q^0=1*0.625^5*1=\\\\P(k=4)=0.0954

c)

P(k\geq4)=P(k=4)+P(k=5)=0.2861+0.0954=0.3815

d)

P(k\leq3)=1-P(x\geq4)=1-0.3815=0.6185

7 0
4 years ago
On a coordinate plane, parallelogram H I J K is shown. Point H is at (negative 2, 2), point I is at (4, 3), point J is at (4, ne
nasty-shy [4]

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Step-by-step explanation:

If (x , y) is the mid-point of a segment whose end points are (x_{1},y_{1})  and  (x_{2},y_{2})  then,

  • x=\frac{x_{1}+x_{2}}{2}
  • y=\frac{y_{1}+y_{2}}{2}

In a parallelogram, its diagonals intersect each other at their mid-points

that means its diagonals bisect each other

∵ HIJK is a quadrilateral

∵ HJ and IK are its diagonals

∵ H = (-2 , 2)

∵ J = (4 , -2)

- Find the mid point of HJ  

∵ M_{HJ}=(\frac{-2+4}{2},\frac{2+-2}{2})

∴ M_{HJ}=(\frac{2}{2},\frac{0}{2})

∴ M_{HJ}=(1,0)

∴ The mid-point of HJ is (1 , 0)

∵ I = (4 , 3)

∵ K = (-2 , -3)

- Find the mid point of IK  

∵ M_{IK}=(\frac{4+-2}{2},\frac{3+-3}{2})

∴ M_{IK}=(\frac{2}{2},\frac{0}{2})

∴ M_{IK}=(1,0)

∴ The mid-point of IK is (1 , 0)

∵ The mid-points of HJ and IK are equal

∴ HJ and IK bisects each other

∴ HIJK is a parallelogram because its diagonals bisect each other

HIJK is a parallelogram because the midpoint of both diagonals is

(1 , 0), which means the diagonals bisect each other

Learn more:

You can learn more about parallelogram in brainly.com/question/6779145

#LearnwithBrainly

6 0
3 years ago
Read 2 more answers
Grant is making muffins for a reunion. The recipe to makes 12 muffins. The recipe for bran muffins makes 18 muffins. He wants to
Lapatulllka [165]

Answer:

a 36

b 3 blueberry, 2 bran

4 0
3 years ago
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