The function to the graph is 6
Answer:
a.) one sample t test
b.) H0 : μ = 59.3
c.) H1 : μ > 59.3
d.) μ = 59.3 ; σ = 39.84
e.) xbar = 79.4 ; s = 61.36
Test statistic = 3.16
Step-by-step explanation:
Given the sample data:
49.00 49.00 49.00 49.00 49.00 63.00 63.00 63.00 63.00 63.00 199.00 199.00 199.00 199.00 199.00 38.00 38.00 38.00 38.00 38.00 48.00 48.00 48.00 48.00 48.00 49.00 63.00 199.00 38.00 48.00
Sample size, n = 30
Using calculator :
xbar from the data above = 79.4
Standard deviation = 61.359
H0 : μ = 59.3
H1 : μ > 59.3
Test statistic :
(Xbar - μ) ÷ (σ/sqrt(n)
σ = 34.83
(79.4 - 59.3) ÷ (34.83/sqrt(30))
20.1 ÷ 6.359
Test statistic = 3.16
Answer: m² + 3m - 10 = 0
Step-by-step explanation:
From the expression, considering
6x + 5 = m
The original expression
( 6x + 5 )² - 10 = -18 - 15
Factorize the right hand expression,
-18 - 15 = -3( 6x - 15 )
Since m = 6x + 5 , we now substitute for m in that expression
m² - 10 = -3m
Now re arrange the equation in the form,
ax² - bx + c = 0
Now back to the equation,
m² + 3m - 10 = 0,
So the equivalent equation will be
m² + 3m - 10 = 0