Please help me I'm strugglingg i will mark you BRAINIYIEST

Mathematics

1 answer:

maw [93]3 years ago

6 0

Answer:

2.5, 7.5, 12, 14.5 , 23.5

Step-by-step explanation:

In a box plot the left is the minimum, then is the 1, 2, and 3rd quartile (interquartile range), then there is the maximum

A 5 number summary is in the same order as a box plot

Now let's identify each part of the box plot

Minimum: 2.5

1'st quartile: 7.5

Median/ 2nd quartile: 12

3rd quartile: 14.5

Maximum: 23.5

Now put it in that order

2.5, 7.5, 12, 14.5, 23.5

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Find the Value of k that will make the function f(x) continuous everywhere.

cricket20 [7]

well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)

$f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k$