In the given problem, it is given that the table is sold at a discount of only one day and that is today. so the table would be have been sold at its original price yesterday. The discount given today is 34% and the sale price for today is $495.
Let us assume the price of the table yesterday = x
Then we can write the equation as
x = 295 * (100/34)
= 29500/34
= 867.64
So the selling price of the table yesterday was $867.64.
Answer:
Option 4: 4¹¹
Step-by-step explanation:
Looking at the problem, I need to work out 4⁴ squared first, which is the same as 4⁸. Then multiply that by 4³ to get 4¹¹. What I did was simply add 3 + (4 * 2), which is 11.
Answer:
29%
Step-by-step explanation:
If 7 is 100% correct then 5 would only be a portion of it
So you need to divide 5 by 7
So 5 divided by 7 is .714 or .71
this means the error was 29%
Answer:
The overview of the given problem is outlined in the following segment on the explanation.
Step-by-step explanation:
The proportion of slots or positions that have been missed due to numerous concurrent transmission incidents can be estimated as follows:
Checking a probability of transmitting becomes "p".
After considering two or even more attempts, we get
Slot fraction wasted,
= ![[1-no \ attempt \ probability-first \ attempt \ probability-second \ attempt \ probability+...]](https://tex.z-dn.net/?f=%5B1-no%20%5C%20attempt%20%5C%20probability-first%20%5C%20attempt%20%5C%20probability-second%20%5C%20attempt%20%5C%20probability%2B...%5D)
On putting the values, we get
= ![1-no \ attempt \ probability-[N\times P\times probability \ of \ attempts]](https://tex.z-dn.net/?f=1-no%20%5C%20attempt%20%5C%20probability-%5BN%5Ctimes%20P%5Ctimes%20probability%20%5C%20of%20%5C%20attempts%5D)
= ![1-(1-P)^{N}-N[P(1-P)^{N}]](https://tex.z-dn.net/?f=1-%281-P%29%5E%7BN%7D-N%5BP%281-P%29%5E%7BN%7D%5D)
So that the above seems to be the right answer.
Line graph (filling space shfskhfskhf)
