Are two clear liquids mix to create a “chunky” solid a chemical of physical change? Why?

Chemistry

1 answer:

marusya05 [52]3 years ago

5 0

Answer:

Well i know that a chemical change is somthing that can not be undone.

This however is a physical change let me explain.

Even though you mixed two chemicals together to create a new substance does NOT mean it is a chemical change. This however is kinda like a water. You can turn water into a ice cube that does not mean it changed what the water is made out of it just changed the form of the water. Kinda like this. A chemical change would be an example of buring a log once that log has turned into ashs it will never be the log it was before.

Explanation:

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Consider the following intermediate chemical equations.(IMAGE) -205.7 kJ -113.4 kJ -14.3 kJ 78.0 kJ

andrey2020 [161]

Answer:

Approximately $-205.7\; \rm kJ$ .

Explanation:

This question can be solved using Hess's Law.

Start by considering: how can the first three reactions (with known $\Delta H$ values) be combined to produce the reaction $\rm CH_4\; (g) + 4\; \rm Cl_2\; (g) \to CCl_4\; (g) + 4\; HCl\; (g)$ ?

Here's one possible combination:

Include the first reaction once, without inverting.
Invert the second reaction and include it once.
Include the third reaction after multiplying all its coefficients by two.

In other words, if $(1)$ , $(2)$ , and $(3)$ denote the three reactions with know $\Delta H$ values, respectively, then $1 \times (1) - 1 \times (2) + 2\times (3)$ will give the required reaction $\rm CH_4\; (g) + 4\; \rm Cl_2\; (g) \to CCl_4\; (g) + 4\; HCl\; (g)$ .

By Hess's Law, the $\Delta H$ value of the reaction $\rm CH_4\; (g) + 4\; \rm Cl_2\; (g) \to CCl_4\; (g) + 4\; HCl\; (g)$ will thus be:

$\begin{aligned}&1 \times \Delta H_1 - 1\times \Delta H_2 + 2\times \Delta H_3\\ &= 1 \times 74.6\; \rm kJ - 1 \times 95.7\; \rm kJ +2 \times (-92.3\; \rm kJ) \\ &= -205.7\; \rm kJ\end{aligned}$ .

7 0

3 years ago

In the reaction of silver nitrate with copper metal, metallic silver comes out of solution, and the solution turns blue. This as

aalyn [17]

Answer:

Single displacement reaction.

Explanation:

Hello!!

In this case, since the reaction between silver nitrate and copper metal is:

$2AgNO_3(aq)+Cu(s)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq)$

As silver was forming silver nitrate, due to the presence of copper, which has the capacity to displace silver out of the salt, we notice the formation of solid silver and a resulting copper (II) nitrate which is blue in aqueous solution.

Therefore, this is a single displacement reaction, because the the lonely copper displaced the silver.

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3 years ago

Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ

Ahat [919]

Answer: The Gibbs free energy of the reaction is 21.32 kJ/mol

Explanation:

The chemical equation follows:

$\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH$