All categories

1 year ago

Describe how water contributes to the fitness of the environment to support life.

1 answer:

6 0

Water contributes to the fitness of the environment to support life by acting as a Solvent for molecules to interact Moderate Earth's climate.

Water contributes to the fitness of the environment to support life in several ways :

Life on Earth began in water and evolved there for 3 billion years before colonizing the land.
Even terrestrial organisms are tied to water.
Most cells are surrounded by water.
Cells are about 70–95% water.
Water is a reactant in many of the chemical reactions of life.
Water is the only common substance that exists in the natural world in all three physical states of matter: solid ice, liquid water, and water vapour.
Water stabilizes air temperatures by absorbing heat from warmer air and releasing heat to cooler air.
Water can absorb or release relatively large amounts of heat with only a slight change in its own temperature.
Water’s high heat of vaporization moderates climate.
Much of the sun’s heat absorbed by tropical oceans is used for evaporation of surface water.
Water is unusual because it is less dense as a solid than as a cold liquid.
Most materials contract as they solidify, but water expands.
At temperatures above 4°C, water behaves like other liquids, expanding as it warms and contracting as it cools.
Water begins to freeze when its molecules are no longer moving vigorously enough to break their hydrogen bonds.
When water reaches 0°C, water becomes locked into a crystalline lattice, with each water molecule bonded to a maximum of four partners.

Learn more about Water here : brainly.com/question/5060579

#SPJ4

You might be interested in

Which of the following is a characteristic property of noble gases? A. They only react with each other B. They do not react chem

tresset_1 [31]

Answer:

B.They do not react chemically

Explanation:

This is because all noble gases haves full outer shell therefore they don’t participate in bonding.They are referred to as inert which means unreactive.

8 0

3 years ago

What are the possible values of ml for l=2

Marrrta [24]

Answer:

-2, -1, 0, 1, 2

Explanation:

There are four types of quantum numbers;

1) Principal quantum number (n)

2) Azimuthal quantum number (l)

3) magnetic quantum number (ml)

4) Spin quantum number (s)

The azimuthal quantum number (l) describes the orbital angular momentum and shape of an orbital while the magnetic quantum number shows the projections of the orbital angular momentum along a specified axis. This implies that the magnetic quantum number shows the orientation of various orbitals along the Cartesian axes. The values of the magnetic quantum number ranges from -l to + l

For l= 2, the possible values of the magnetic quantum number are; -2, -1, 0, 1, 2

5 0

2 years ago

What is the volume of 2 mol of chlorine gas at STP? 2.0 L 11.2 L 22.4 L 44.8 L

nirvana33 [79]

Answer:

44.8 L

Explanation:

Using the ideal gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At Standard temperature and pressure (STP);

P = 1 atm

T = 273K

Hence, when n = 2moles, the volume of the gas is:

Using PV = nRT

1 × V = 2 × 0.0821 × 273

V = 44.83

V = 44.8 L

7 0

2 years ago

. Determine the standard free energy change, ɔ(G p for the formation of S2−(aq) given that the ɔ(G p for Ag+(aq) and Ag2S(s) are

olga nikolaevna [1]

Answer: The standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

Explanation:

We are given:

$K_{sp}\text{ of }Ag_2S=8\times 10^{-51}$

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K$

where,

$\Delta G^o$ = standard Gibbs free energy = ?

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

K = equilibrium constant or solubility product = $8\times 10^{-51}$

Putting values in above equation, we get:

$\Delta G^o=-(8.314J/K.mol)\times 298K\times \ln (8\times 10^{-51})\\\\\Delta G^o=285793.9J/mol=285.794kJ$

For the given chemical equation:

$Ag_2S(s)\rightleftharpoons 2Ag^+(aq.)+S^{2-}(aq.)$

The equation used to calculate Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_f_{(product)}]-\sum [n\times \Delta G^o_f_{(reactant)}]$

The equation for the Gibbs free energy change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(Ag^+(aq.))})+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times \Delta G^o_f_{(Ag_2S(s))})]$

We are given:

$\Delta G^o_f_{(Ag_2S(s))}=-39.5kJ/mol\\\Delta G^o_f_{(Ag^+(aq.))}=77.1kJ/mol\\\Delta G^o=285.794kJ$

Putting values in above equation, we get:

$285.794=[(2\times 77.1)+(1\times \Delta G^o_f_{(S^{2-}(aq.))})]-[(1\times (-39.5))]\\\\\Delta G^o_f_{(S^{2-}(aq.))=92.094J/mol$

Hence, the standard free energy change of formation of $S^{2-}(aq.)$ is 92.094 kJ/mol

8 0

3 years ago

Air is composed of nitrogen oxygen and based on that information air can be described as

Vilka [71]

Answer:

Air can be described as: Mass and Mixture of Gases

Mass is defined as how much stuff an object contains - and by stuff, I mean matter, like atoms and molecules. And even though you can't see it, air has a lot of atoms and molecules. Air is a gas (as opposed to a liquid or a solid) and contains about 78% nitrogen, 21% oxygen, and 1% argon.

Explanation:

4 0

3 years ago