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yaroslaw [1]
3 years ago
6

Pls help middle school math!!

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0
R = square root of (A/pi)
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Anna truncated the decimal expansion of x to find the best approximation. On a number line, the location of x is between 10.9 an
podryga [215]

Answer:

Well to estimate a decimal the best option would be to round it to.

10 or 11 (For 10.9)

11 (For 11.1)

and since two of them equal 11. 

The estimation would be 11.

I hoped this helped.

3 0
3 years ago
?simplified the expression
larisa [96]
The first two negatives cancel out and you're left with positive 4. Now go inside the square root and do the exponent. -4*-4 = 16. Then do the -4*3*1 = -12. Do 16-12 = 4. now the square root of 4 = 2. at the dominator is 2*3 = 6. right now they problem should look like 4+- 2/ 6. from there you split the problem in two. so you have 4+2/6   &     4-2/6     then you solve both problems.
           6/6               2/6
             1                  1/3
1 & 1/3 are your answers. I hope this helped!
5 0
3 years ago
joshua can wash 5 cars in 1 hour and jason can wash 3 cars in one hour. at this rate, how long will it yake joshua and jason to
zvonat [6]

The answer is 3 hours  40 minutes

3 0
4 years ago
PLEASE HELP ME! i think its A
natali 33 [55]

Answer:

The answer is 3rd option.

Step-by-step explanation:

In a graph, domain is always represented by the x-axis. So by looking at the graph, the minimum value of x is -2. We can know that x ≥ -2.

5 0
3 years ago
Read 2 more answers
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
3 years ago
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