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4 years ago

What are the domain and range of the quadratic parent function

1 answer:

6 0

The domain is all real numbers and the range is all the reals at or above the vertex y coordinate (if the coefficient on the squared term is positive) or all the reals at or below the vertex (if said coefficient is negative).

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The formula for this.(sorry for the horrible graph it was hand drawn

ozzi

Answer:

y = 1/2x+5

Step-by-step explanation:

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3 years ago

How can you determine if two expressions are equivalent?

Vladimir [108]

Simplify them until they can be simplified no more, then compare both sides.

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3 years ago

Solve Please <br> (⁴√2+⁴√8)²

hichkok12 [17]

Answer:

Simplified = 4 + 3 $\sqrt{2}\\$ , Decimal = 8.2426...

Step-by-step explanation:

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3 years ago

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On a coordinate plane, a straight line and a parallelogram are shown. The straight line has a negative slope and has a formula o

alexira [117]

Answer:

(1,3)

Step-by-step explanation:

edge 2020

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4 years ago

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Triangle ABC was dilated with the origin as the center of dilation to create triangle A'B'C'. The triangle was dilated using a s

victus00 [196]

Answer:

$A'(-0.25,0.75)\\\\B'(1.75,-0.25)\\\\C'(-1,-0.25)$

Step-by-step explanation:

A Dilation is defined as a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1, the image obtained after the dilation is smaller than the pre-image and it is an "Reduction".

In this case you know that the triangle ABC was dilated by this scale factor:

$scale\ factor=\frac{1}{4}$

With the origin as the center of dilation.

Since:

$0$

It is a Reduction.

You can identify that the vertices of the triangle ABC are:

$A(-1,3)\\\\B(7,-1)\\\\C(-4,-1)$

So you need to multiply the coordinates of each vertex of the triangle ABC by $\frac{1}{4}$ , in order to get the coordinates of the triangle A'B'C. Then, you get:

$A'=(\frac{1}{4}(-1),\frac{1}{4}(3))=(-0.25,0.75)\\\\B'(\frac{1}{4}(7),\frac{1}{4}(-1))=(1.75,-0.25)\\\\C'(\frac{1}{4}(-4),\frac{1}{4}(-1))=(-1,-0.25)$

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3 years ago