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tatyana61 [14]
3 years ago
9

What are the zeros of f(x) = x^2 - x- 12? Please explain if you can.

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

4 and -3

Step-by-step explanation:

So our function is f(x) = x² - x -12

We need to find factors such that 0 = x² - x -12

So, it looks something like this 0 = (x - a)(x - b)

We know that the first term is x², which can only be obtained if we multiply x by another x.

Now, we need to find the other terms a and b. We know that a × b = -12

The correct answer would be that a = 4 and b = -3

0 = (x - 4)(x + 3)

We know this because, if we multiply this out, we get x² + 3x -4x -12, which can be simplified to x² -x -12.

Our zeroes are the values of x that this equation 0 = (x - 4)(x + 3) is true. What values of x will make this zero?

4 and -3

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Show all steps!!!
Lunna [17]
-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3
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\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}
=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}
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3 years ago
At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad
sertanlavr [38]

<u>Answer:</u>

The length of the person’s shadow is 5.7ft

<u>Explanation:</u>

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the  rules of trigonometry

\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}

\frac{a}{b}=\frac{c}{d}

\frac{35}{50}=\frac{4}{d}

35d=200

d=\frac{200}{35}

d=5.7ft  

Hence, The length of the person’s shadow is 5.7ft.

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Answer:

25

Step-by-step explanation:

3^2=9

-2^4=16

9+16=25

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