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3 years ago

Does anyone do savvas realize

Mathematics

2 answers:

il63 [147K]3 years ago

8 0

No!..........................

Aleksandr-060686 [28]3 years ago

3 0

Answer:

Yes, I do for my Spanish class!

Do you have any questions about it?

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Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by

a_sh-v [17]

Answer:

Dimension of the box is $16.1\times 7.1\times 2.45$

The volume of the box is 280.05 in³.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is $L=21-2h$

The width of the box is $W=12-2h$

The volume of the box is $V=L\times W\times H$

$V=(21-2h)\times (12-2h)\times h$

$V=(21-2h)\times (12h-2h^2)$

$V=252h-42h^2-24h^2+4h^3$

$V=4h^3-66h^2+252h$

To maximize the volume we find derivative of volume and put it to zero.

$V'=12h^2-132h+252$

$0=12h^2-132h+252$

Solving by quadratic formula,

$h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}$

$h=\frac{132\pm72.99}{24}$

$h=2.45,8.54$

Now, substitute the value of h in the volume,

$V=4h^3-66h^2+252h$

When, h=2.45

$V=4(2.45)^3-66(2.45)^2+252(2.45)$

$V\approx 280.05$

When, h=8.54

$V=4(8.54)^3-66(8.54)^2+252(8.54)$

$V\approx -170.06$

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is $L=21-2(2.45)=16.1$

The width of the box is $W=12-2(2.45)=7.1$

So, Dimension of the box is $16.1\times 7.1\times 2.45$

6 0

4 years ago

Based on a sample of 150 textbooks at the store, you find an average of 70.69 and a standard deviation of 29.6. The point estima

Ugo [173]

Answer:

Step-by-step explanation:

Given that:

The sample size = 150

The sample mean = 70.69

The standard deviation = 29.60

The sample mean is equal to the point estimate of the population = 70.69

At 99% confidence interval level is:

∝ = 1 - 0.99

∝ = 0.01

The critical value:

$Z_{\alpha/2} = Z_{0.01/2} \\ \\ Z_{0.005} = 2.58 \ using \ Z \ tables$

The Margin of error = $Z_{\alpha/2} \times \dfrac{\sigma}{\sqrt{n}}$

$= 2.58 \times \dfrac{29.6}{\sqrt{150}}$

= 2.58 × 2.4168

≅ 6.235

At 99% confidence interval; the estimate of the population mean lies within the interval:

= $\overline x - E < \mu \ < \overline x + E$

= 70.69 - 6.235 < μ < 70.69 + 6.235

= 64.455 < μ < 76.925

= (64.455 , 76.925 )

6 0

3 years ago

There are 400 people in a talent show in middle school in February 62% of students performed in the band concert how many studen

grandymaker [24]

Answer:

62% of 400 = 248

Step-by-step explanation:

62% of 400 = 0.62 × 400 = 248

7 0

4 years ago

Compare the values of each digits in the decimal 962.69 , compare the 6 in the tens place than the 6 in the tenths place.

givi [52]

I think the answer would be like... The 6 in each place is worth a different amount. Like just the 6 in the tenths place is worth less than the 6 in the tens place.

7 0

4 years ago

10x+12y=15<br><br> solve for y

Whitepunk [10]

Answer:

10x + 12y = 15

12y = 15 - 10x

y = 15 - 10x / 12 (15 minus 10x all divided by 12) [Answer]

4 0

3 years ago