Combine like terms
e)= 3t^3
f) = 2m^2 + 5m
g) = 3k^3 + 4
h) = 8y^2 - 2y + 6
hope it helps
So the answer is
(<span>x^2 plus or minus 6)(x^2 plus or minus 6)
an easy way to do this is to only look at plus or minus 6
x^4 <u><em>- 12</em></u>x^2 + <u><em>36 (-12 and 36)
</em></u><em />
<u><em /></u>6 x 6 = 36
<em />6 + 6 </span>≠ -12 (x^2 + 6)(x^2 + 6) is incorrect
<span><u><em>
</em></u><em><u /></em><u />6 x -6 </span>≠ 36
<span><em />6 + -6 </span>≠ -12 (x^2 - 6)(x^2 + 6) is incorrect
<span><em /><em>
</em><em />-6 x -6 = 36
<em />-6 + -6 = -12 </span><span>(x^2 - 6)(x^2 - 6) is correct
</span><u><em>
the answer is (1)
</em></u>
Answer:
answer is a . x²-8x+16=32
x²-8x=32-16
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, but I would show you how to solve it.
Solution:
A circle is the locus of a point such that its distance from a fixed point which is its center is always constant.
The tire has the shape of a circle. Therefore the distance the tire covers if it is pushed around once is the same as the circumference of the tire. The circumference is given by:
Circumference = 2πr; where r is the radius of the tire
Let us assume that the tire has a radius of 7 cm. Hence:
Circumference = 2π(7) = 44 cm
If the tire moves around 5 times, the distance covered = 5 * circumference of tire = 5 * 44 cm = 220 cm
