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Mathematics

2 answers:

emmasim [6.3K]1 year ago

8 0

Answer:

A.) Omar's withdrawal involves more money, because $|-15| >|10|$ .

Step-by-step explanation:

Ira Lisetskai [31]1 year ago

7 0

the answer does be A

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hello my frands teheehee free answers maybe even giving out brainliest I dont know how to spell don't attack me

Aleks04 [339]

What’s the question

7 0

2 years ago

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An angle measures 48.4° less than the measure of its complementary angle. What is the measure of each angle?

Gennadij [26K]

Answer:

The angles are 69.2 degrees and 20.8 degrees

Step-by-step explanation:

Complementary angles, when added together, = 90°

We’ll call the first unknown angle a and the second angle b

b = a - 48.4

a + b = 90

So let’s substitute in for b in the second equation:

a + a - 48.4 = 90

2a - 48.4 = 90

2a = 138.4

a = 69.2

69.2 - 48.4 = 20.8 = b

Now, does a + b = 90?

69.2 + 20.8 = 90

Lmk if you have questions

3 0

2 years ago

What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)

timurjin [86]

$Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}
$ $
 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}$ $A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}$ $Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}$