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alexira [117]
2 years ago
13

Identify the subsets of real numbers to which the number 25√ belongs.

Mathematics
1 answer:
pashok25 [27]2 years ago
5 0

Answer:

Choose all that apply.

Step-by-step explanation:

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Madison made the following table to record the height of each person in her family.
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Leto [7]

Answer:

 - The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

- The scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse} and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).

Step-by-step explanation:

 You can observe in the figure attached that  "AC" is the distance between the Sun and the shooting star.

Knowing the distance between the Earth and the Sun "y" and the angle x°,  the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.

 This is:

cos\alpha=\frac{adjacent}{hypotenuse}

In this case:

\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC

Therefore, the scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse} , and solve for the distance between the Sun and the shooting star "AC":

cos(x\°)=\frac{y}{AC}

AC=\frac{y}{cos(x\°)}

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What is the inverse and restricted domain of the equation 8x^2-3
kari74 [83]

Answer:  \bold{y=\pm \dfrac{\sqrt{2(x+3)}}{4},\qquad x\neq -3}

<u>Step-by-step explanation:</u>

y = 8x² - 3            (Restriction: none -  x is All Real Numbers)

The inverse is when you swap the x's and y's and then solve for y

x = 8y² - 3            <em>swapped the x and y</em>

x + 3 = 8y²           <em>added 3 to both sides</em>

\dfrac{x+3}{8}=y^2           <em>divided both sides by 8</em>

\sqrt{\dfrac{x+3}{8}}=\sqrt{y^2}           <em>square rooted both sides</em>

\pm \sqrt{\dfrac{x+3}{8}}=y           <em>simplified</em>

\pm \sqrt{\dfrac{x+3}{8}\bigg(\dfrac{2}{2}\bigg)}=y           rationalized the denominator

\pm \sqrt{\dfrac{2(x+3)}{16}}=y           <em>simplified</em>

\pm \dfrac{\sqrt{2(x+3)}}{4}=y           <em>simplified</em>

<u>Restriction:</u>

The radical <em>(inside the square root sign)</em> cannot be negative

→  2(x + 3) ≥ 0

      x + 3 ≥ 0         <em>divided both sides by 2</em>

      x       ≥ -3         <em>subtracted 3 from both sides</em>



4 0
3 years ago
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