Answer:
½ ln 3
Step-by-step explanation:
∫ sec²x / tan x dx
If u = tan x, then du = sec²x dx.
∫ du / u
ln|u| + C
ln|tan x| + C
Evaluate between π/4 and π/3.
ln|tan(π/3)| + C − (ln|tan(π/4)| + C)
ln|√3| + C − ln|1| − C
ln(√3)
½ ln 3
3738383792639263846736283
2/3+3/4=17/12=1.417 This is the anwser
We use the fact that x2+y2=1 This is the equation of the unit circle.
We know that x=-4/5, so plug this in and solve for y
x2+y2=1 <span>(−4/5)^2+y2=1</span> 16/25+y2=1 y2=1−16/25 y2=9/25 <span>y=−square root of 9/ 25</span>
y = -3/5
Answer:
y - 1 = 0
Step-by-step explanation:
We know that Equation of a line is given by,
y - y₁ / x - x₁ = y₂ - y₁ / x₂ - x₁
Let A(-2,1) and B(2,1)
x₁ = -2 ; x₂ = 2 ; y₁ = 1 ; y₂ = 1
Substituting the values,
y - 1 / x - (-2) = 1 - 1 / 2 - (-2)
y - 1 / x + 2 = 0
y - 1 = 0
