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3 years ago

Find the equation of this line. y = [ ? ]x + [ Simplify your answer and enter as an integer.

Mathematics

2 answers:

lys-0071 [83]3 years ago

4 0

Answer:

y= 2x -2

Step-by-step explanation:

........................................

const2013 [10]3 years ago

3 0

Answer: x = - 1/2

Step-by-step explanation:

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Solve the proportion 2x + 1/x + 1 = 14/3x-1

monitta

$\frac{2x+1}{x+1} = \frac{14}{3x-1} \ \ \Leftrightarrow\ \ (2x+1)(3x-1)=14(x+1)\ \ and\ \ x\in R-\{-1; \frac{1}{3}\}\\ \\6x^2-2x+3x-1=14x+14\\6x^2-13x-15=0\ \ \Rightarrow\ \ \Delta=(-13)^2-4\cdot6\cdot(-15)=169+360=529\\ \\ \sqrt{\Delta} =2\\ \\x_1= \frac{13-23}{2\cdot6} = \frac{-10}{12}=- \frac{5}{6}\ \in D\ \ \ and\ \ \ x_2= \frac{13+23}{2\cdot6} = \frac{36}{12}=3\ \in D$

6 0

4 years ago

Read 2 more answers

Find the fraction of Chandler's comic book collection that is made

m_a_m_a [10]

Im not sure what your asking

8 0

3 years ago

a square red rug has a purple square in the center. the side length of the purple square is x inches. the width of the red band

Bumek [7]

Answer:

Area of red band is $(20x + 100) inch^{2}$

Step-by-step explanation:

We know that area of square = $side^{2}$

Please refer to the attached figure, we have to calculate the area of red band.

Required area = Area of square ABCD - Area of purple square

Side of purple square = $x$

So, area of purple square = $x^{2}$

ABCD is a square with purple square at the center and there is symmetry in the figure.

So, width of red band towards both the end is 5 inches.

$\Rightarrow \text{side of }ABCD = 5 + 5 +x = (x+10) inches$

Required area = $(x+10)^{2} - x^{2}$

Using formula $a^{2} - b^{2} = (a-b)\times (a+b)$

$\Rightarrow (x+10-x)(x+10+x)\\\Rightarrow (10)(2x+10)\\\Rightarrow (20x+100)$

Hence, Area of red band is $(20x + 100) inch^{2}$

5 0

3 years ago

A triangular plot of land has one side along a straight road measuring 294 feet. a second side makes a 63degrees angle with the

creativ13 [48]

The side across from the 63° angle is 299.5 ft and the side across from the 56° angle is 278.7 ft.

We will use the Law of Sines to solve this. First, the angle across from the 63° angle:
sin 61/294 = sin 63/x

Cross multiply:
x*sin 61 = 294 sin 63

Divide by sin 61:
(x sin 61)/(sin 61) = (294 sin 63)/(sin 61)
x = 299.5

For the side across from the 56° angle:
sin 61/294 = sin 56/x

Cross multiply:
x*sin 61 = 294 sin 56

Divide both sides by sin 61:
(x sin 61)/(sin 61) = (294 sin 56)/(sin 61)
x = 278.7

6 0

3 years ago

Determine whether the three points are the vertices of a right triangle.

Jobisdone [24]

Yes I have graphed them and they form a 90 degree angle

5 0

3 years ago