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LenaWriter [7]
3 years ago
14

Find Average Rate of Change from Table

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0

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The rent for an apartment goes down by $35 per month.<br><br> What integer represents the situation?
Liula [17]

are there any options? or no

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2 years ago
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Help please 1. Describe the transformations necessary to transform the graph of
natta225 [31]

Here are all the steps, and what they do:

STEP 1: HORIZONTAL TRANSLATION

We transform

x^2\mapsto (x-1)^2

The general transformation is

f(x)\mapsto f(x+k)

These transformations translate the graph horizontally, k units to the left if k>0, k units to the right if k<0.

In this case, k = -1, so we translate the original graph 1 unit to the right.

STEP 2: VERTICAL STRETCH

We transform

(x-1)^2\mapsto 3(x-1)^2

The general transformation is

f(x)\mapsto kf(x)

These transformations stretch the graph vertically. The graph expands if |k|>1, while it shrinks if 0<|k|<1. If k is negative, we also reflect the graph with respect to the x axis.

In this case, k = 3, so we stretch the graph vertically by a factor 3.

STEP 3: VERTICAL TRANSLATION

We transform

3(x-1)^2\mapsto 3(x-1)^2+4

The general transformation is

f(x)\mapsto f(x)+k

These transformations translate the graph vertically, k units up if k>0, k units down if k<0.

In this case, k = 4, so we translate the graph 4 units up.

So, we start from the original graph of f(x)=x^2 and we:

  • Translate it 1 unit to the right
  • Stretch it vertically by a factor 3
  • Translate it 4 units up

(the order is important!)

to get the graph of g(x)=3(x-1)^2+4

4 0
3 years ago
Determine if the two expressions are equivalent and if so name the property that is being used.
Vinil7 [7]

Answer: i really dont know

Step-by-step explanation: but 46

6 0
3 years ago
Standardization of Normal Distribution is the process of
n200080 [17]

Answer:

Step-by-step explanation:

Standardizing a normal distribution is to convert a normal distribution to the standard normal distribution. In real-world applications, a continuous random variable may have a normal distribution with a value of the mean that is different from 0 and a value of the standard deviation that is different from 1.

7 0
2 years ago
A couple quick algebra 1 questions for 50 points!
kkurt [141]

Answer:

Question 6) Neither (Not an inverse variation)

Question 7) Inverse variation

Question 8) Inverse variation

Step-by-step explanation:

These are the two formulas we need to know prior to solving the question.

Direct variation: c times x

Inverse variation: c times 1/x --> c/x

- Here, c is the constant

6. y = x + 7

This is neither. It is not in the form of a direct, or inverse variation, so it does not belong in any category.

7. 14 = xy

This equation is an inverse variation.

xy = 14

y = 14/x

14 is the constant, and the format is the same as for an inverse variation.

8. x = -8/y

This equation is an inverse variation.

yx = -8

y = -8/x

-8 is the constant, and the format is the same as for an inverse variation.

So we can conclude that questions 7 and 8 is an inverse variations, while question 6 isn't.

6 0
2 years ago
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