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Bingel [31]
3 years ago
12

If the hypotenuse of a right triangle is 20 cm and one of the legs is 16 cm, how long is the other leg?

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
Because this is a triangle and we know that we can use the Pythagorean Theorem to find the hypotenuse we just plug in the numbers. But because you have the hypotenuse already you will subtract the leg from the hypotenuse.

A^2+B^2=C^
16^2+B^2=20^2
256+B^2=400 subtract 256 from both sides
B^2=144 now take the square root of both sides
B=12

The second leg is 12 cm long. Your answer is B, the second answer.
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\huge \boxed{\mathfrak{Question} \downarrow}

  • \large\sf\frac{1}{5} (4 - 3x) =  \frac{1}{7} (3x - 4) \\

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\frac{1}{5} (4 - 3x) =  \frac{1}{7} (3x - 4) \\

Use the distributive property to multiply 1/5 by 4-3x.

\frac{1}{5}\times 4+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right)  \\

Multiply 1/5 and 4 to get 4/5.

\frac{4}{5}+\frac{1}{5}\left(-3\right)x=\frac{1}{7}\left(3x-4\right)  \\

Multiply 1/5 and -3 to get -3/5.

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Use the distributive property to multiply 1/7 by 3x-4.

\frac{4}{5}-\frac{3}{5}x=\frac{1}{7}\times 3x+\frac{1}{7}\left(-4\right)  \\

Multiply 1/7 and 3 to get 3/7 & 1/7 × -4 to get -4/7.

\frac{4}{5}-\frac{3}{5}x=\frac{3}{7}x-\frac{4}{7}  \\

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\frac{4}{5}-\frac{3}{5}x-\frac{3}{7}x=-\frac{4}{7}  \\

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\frac{4}{5}-\frac{36}{35}x=-\frac{4}{7}  \\

Subtract 4/5 from both sides.

-\frac{36}{35}x=-\frac{4}{7}-\frac{4}{5}  \\

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Subtract 28 from -20 to get -48.

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Multiply both sides by -\frac{35}{36}\\, the reciprocal of -\frac{36}{35}\\.

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x=\frac{1680}{1260}  \\

Reduce the fraction 1680/1260 to its lowest terms by extracting and cancelling out 420.

\huge \boxed{ \boxed{ \bf \: x=\frac{4}{3}  \approx \: 1.33}}

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