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Bingel [31]
3 years ago
12

If the hypotenuse of a right triangle is 20 cm and one of the legs is 16 cm, how long is the other leg?

Mathematics
1 answer:
siniylev [52]3 years ago
6 0
Because this is a triangle and we know that we can use the Pythagorean Theorem to find the hypotenuse we just plug in the numbers. But because you have the hypotenuse already you will subtract the leg from the hypotenuse.

A^2+B^2=C^
16^2+B^2=20^2
256+B^2=400 subtract 256 from both sides
B^2=144 now take the square root of both sides
B=12

The second leg is 12 cm long. Your answer is B, the second answer.
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Step-by-step explanation:

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2 years ago
Help please?<br><br><br> What are the factors of the product represented below?
Ilia_Sergeevich [38]

Answer:

B

Step-by-step explanation:

count how many x^2 there are because they would tell you what your answer is.

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2 years ago
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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

  • 5 red balls

  • 4 blue balls

  • 6 yellow balls

  • 10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

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\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
What is the distance from X to Y?
Rama09 [41]

Answer:

Step-by-step explanation:

To find the distance between two points, (A, B) and (C, D), you can use the following distance formula:

distance = \sqrt{(A - C)^{2} + (B - D)^{2}}

Plugging in the points from the problem, you'll get the following:

\sqrt{(0 - 9)^{2} + (6 - (-6))^{2}}

\sqrt{(-9)^{2} + (12)^{2}}

\sqrt{81 + 144}

\sqrt{225}

15

3 0
3 years ago
Read 2 more answers
Please help asap!!!!!!!!!!!
mars1129 [50]
X = 59, y = 44

2x + 18 + x - 15 = 180
3x + 3 = 180
3x = 177
x = 59

x - 15 = y
59 - 15 = y
44 = y
6 0
2 years ago
Read 2 more answers
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