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3 years ago

I need help asap :)/):)

Mathematics

1 answer:

lina2011 [118]3 years ago

6 0

Answer:

it is the first choice

Step-by-step explanation:

-4+2x>-4

solve for x

add four to both sides to get the 2x alone

2x> 0

divide the 2 from both sides to get the x alone

x>0

answer: x>0

hope this helps!

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Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)

muminat

Question:

Factor $64-x^2$

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: $(8+x)(8-x)$ is the factor

Explanation:

Given that the expression is $64-x^2$

We need to find the factor of the given expression.

Let us rewrite the expression as $8^2-x^{2}$

Since the expression is of the form $a^2-b^2$ , let us use the identity $a^2-b^2=(a+b)(a-b)$

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

$8^2-x^{2}=(8+x)(8-x)$

Thus, the factor of the expression is $(8+x)(8-x)$

Hence, Option B is the correct answer.

4 0

3 years ago

And ice cream factory makes 190 quarts of ice cream in five hours how many quarts could be made in 36 hours what was the rate pe

levacccp [35]

190/5 = 38

So, they can make 38 quarts in an hour.

38 * 36 = 1,368

They can make 1,368 quarts in 36 hours.

3 0

3 years ago

Help with #9<br> ASAP PLEASE.

yawa3891 [41]

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5 0

3 years ago

F(x) = x + 2 when x = 10

murzikaleks [220]

Answer:

f(10) = 12

Step-by-step explanation:

f(x) = x + 2

Substitute x for 10.

f(10) = 10 + 2

f(10) = 12

8 0

3 years ago

Read 2 more answers

You have D dollars to buy fence to enclose a rectangular plot of land (see figure at right). The fence for the top and bottom co

alex41 [277]

The perimeter of the rectangular plot of land is given by the expression below

$P=2x+2y$

On the other hand, since the available money to buy fence is D dollars,

$\begin{gathered} D=4(2x)+3(2y) \\ \Rightarrow D=8x+6y \\ D\rightarrow\text{ constant} \end{gathered}$

Furthermore, the area of the enclosed land is given by

$A=xy$

Solving the second equation for x,

$\begin{gathered} D=8x+6y \\ \Rightarrow x=\frac{D-6y}{8} \end{gathered}$

Substituting into the equation for the area,

$\begin{gathered} A=(\frac{D-6y}{8})y \\ \Rightarrow A=\frac{D}{8}y-\frac{3}{4}y^2 \end{gathered}$

To find the maximum possible area, solve A'(y)=0, as shown below

$\begin{gathered} A^{\prime}(y)=0 \\ \Rightarrow\frac{D}{8}-\frac{3}{2}y=0 \\ \Rightarrow\frac{3}{2}y=\frac{D}{8} \\ \Rightarrow y=\frac{D}{12} \end{gathered}$

Therefore, the corresponding value of x is

$\begin{gathered} y=\frac{D}{12} \\ \Rightarrow x=\frac{D-6(\frac{D}{12})}{8}=\frac{D-\frac{D}{2}}{8}=\frac{D}{16} \end{gathered}$ <h2>Thus, the dimensions of the fence that maximize the area are x=D/16 and y=D/12.</h2><h2>As for the used money,</h2> $\begin{gathered} top,bottom:\frac{8D}{16}=\frac{D}{2} \\ Sides:\frac{6D}{12}=\frac{D}{2} \end{gathered}$ <h2>Half the money was used for the top and the bottom, while the other half was used for the sides.</h2>

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1 year ago