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Nat2105 [25]
3 years ago
9

Problem type join results unknown

Mathematics
1 answer:
Allisa [31]3 years ago
8 0

<u>Not sure what you are asking for, but,</u>

<u>Here is an example of a JRU (Join Result Unknown)  word problem</u>:

There were _____ kids on the playground. ____ more kids came onto the playground. How many kids are on the playground?

<u>Here is an example of a JCU (Join Change Unknown)  word problem:</u>

There were ____ kids on the playground. Some more kids came on the playground. Now there are ____ kids on the playground. How many kids came on the playground?

<u> Here is an example of a JSU (Join Start Unknown)  word problem:</u>

Some kids were on the playground. ____ kids came on the playground. Now there are ____ kids on the playground. How many kids were on the playground at the beginning?



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1. The answer is 0.425

2. the answer is 0.425

3. the answer is 0.2125

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3 years ago
The decimal form of a fraction is called a what​
Yuri [45]

Answer:

Hello Adam here!

Step-by-step explanation:

The numbers that are represented by decimal numerals are the decimal fractions (sometimes called decimal numbers), that is, the rational numbers that may be expressed as a fraction whose denominator is a power of ten.

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Y = - 3x + 6
dusya [7]

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Step-by-step explanation:

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Read 2 more answers
How to solve for shaded area
tamaranim1 [39]

Answer:

(a)  12.96 ft²

(b)  21.5 in²

Step-by-step explanation:

(a) For the first diagram

Area of the shaded region (A) = Area of Tripezium- area of circle

A = [1/2(a+b)h]-[πr²]............... Equation 1

Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.

From the diagram,

Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.

Constant: π = 3.14

Substitute these values into equation 1

A = [12(15+6)/2]-(3.14×6²)

A = 126-113.04

A = 12.96 ft²

(b) For the second diagram,

Area of the shaded region (A') = Area of square- area of circle

A' = (L²)-(πr²)............. Equation 2

Where L = lenght of one side of the square, r = radius of the circle

From the diagram,

Given: L = 2r = (2×5) = 10 in, r = 5 in

Substitute these values into equation 2

A' = (10²)-(3.14×5²)

A' = 100-78.5

A = 21.5 in²

5 0
3 years ago
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