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Ugo [173]
3 years ago
13

This graph shows the solution to which inequality?

Mathematics
1 answer:
Butoxors [25]3 years ago
7 0

Answer:

letss seeee

Step-by-step explanation:

c.

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What type of triangle can a right triangle be?
Dimas [21]

Answer:

acute

Step-by-step explanation:

Please mark brainliest and have a great day!

6 0
3 years ago
Algebra 2: PLEASE HELP ME!!
vfiekz [6]

Looks more like Trig than Algebra II

They want us to apply the sum angle formula to \sin(x + \frac{5 \pi}{6})

5π/6 is 150°; I find it easier to think in degrees.

When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.

The sine sum angle formula is

\sin(a+b) = \sin a \cos b + \cos a \sin b

\sin(x+\frac{5\pi}{6}) = \sin x  \cos \frac{5\pi}{6} + \cos x \sin \frac{5\pi}{6}

We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2

\sin(x+\frac{5\pi}{6}) = \frac 3 5  (- \sqrt{3}/2)  + \frac 4 5 (1/2)

\sin(x+\frac{5\pi}{6}) = \dfrac{ 4- 3\sqrt{3}}{10}

Third choice

3 0
4 years ago
This graph shows linear
tamaranim1 [39]

Answer:

x = 1

Step-by-step explanation:

So first we have to identify what f(x) and g(x) equals. We can do this by looking at their y-intercept and determining their slope, by its rise/run

the two equations are:

y = -2x - 1

y = x + 2

now we solve

f(x) + g(x) = 0

substitute

-2x - 1 + x + 2 = 0

simplify

-x + 1 = 0

divide by -1

x - 1 = 0

add one on both sides

x = 1

7 0
3 years ago
Solve the equation 17=5k-3
Gre4nikov [31]

Answer:

k = 4

Step-by-step explanation:

17 = 5k - 3

+3.         +3

20/5 = 5k/5

4 = k

k = 4

6 0
3 years ago
Read 2 more answers
PQRS is parallelogram,QM is the height of Q to SR and ON is the height from Q to PS.It SR =12 cm and QM =7.6 cm find the area of
Oksanka [162]

Given: SR=12cm, QM=7.6cm, PS=8cm.

Area of parallelogram=base×height

=12×7.6=91.2cm2.

Area of parallelogram=base×height

⇒91.2=8×QN

⇒QN=891.2=11.4cm.

5 0
3 years ago
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