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Vinvika [58]
3 years ago
9

Using F=ma, explain why a train is more difficult to start moving and more difficult to bring to a stop than an average sized ca

r.
Physics
1 answer:
seropon [69]3 years ago
6 0

Answer:

M_Train>> m_car    a_train <a_car

Explanation:

To start the movement of the train or the car, the motorcycle applies a force on the wheels, which starts the acceleration in the case of the train, it has a much greater mass than that of the car, for which to obtain the same acceleration necessary a much greater force

         a = F / m

as the mass of the train is greater than that of the car.

         a_train <a_car

Something similar happens when the vehicles stop, the engine stops applying force forward and the brakes apply a force backward that creates a negative acceleration that slows down, again as the mass of the train is much greater than the of the car its negative acceleration is much less.

   

It is good to clarify that to compensate for this the trains have a braking system on all wheels

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2.5mA

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A firm current ratio is 1. 0 and its quick ratio is 1. 0. If current liabilities are 12300, what are its inventories?
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A firm current ratio is 1. 0 and its quick ratio is 1. 0. If current liabilities are 12300 then its inventories will be 12300

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2 years ago
Calculate the force of gravity between a comet with a mass of 500kg and a small asteroid with a mass of 20kg that is separated b
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▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent gravitational force is ~

  • F  \approx1.48\times 10 {}^{ - 7}  \: \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where,

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  • m_1 = mass of 1st object = 500 kg

  • m_2 = mass of 2nd object = 20kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 2.12 m

Let's calculate the force ~

  • F = \dfrac{6.674   \times 10 {}^{ - 11} \times 500 \times 20}{(2.12) {}^{2} }

  • F = \dfrac{6.674  \times 10 {}^{ - 11} \times 10 {}^{4} }{4.4944}

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Intro to Springs and Hooke’s law
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Answer:

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s is the distance the meson travelled before coming to rest.

So,

 

s = 0.1 m

The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.  

5 0
3 years ago
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