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ratelena [41]
3 years ago
14

I NEED HELP ASAP!!!!!

Mathematics
2 answers:
Elina [12.6K]3 years ago
6 0
Step 2 16 + 15 is not 21
Julli [10]3 years ago
4 0

Answer:

x actually = 13 and its step 2

Step-by-step explanation:

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9 < 11, so 9(5) < 11(5) true or false?
Zolol [24]
It is true since you’re multiplying the same number on both the sides
7 0
3 years ago
Round 49.87654321 to the nearest tenth
schepotkina [342]
49.9 is the answer
hope it helps ya :D
8 0
3 years ago
Determine if direct variation x-2y=0
Fofino [41]

Answer:

x-2y=0 is a direct variation

Step-by-step explanation:

Direct variation is of the form

y= kx

Can we get the equation in that form

x-2y =0

Add 2y to each side

x-2y+2y =0_2y

x=2y

Divide each side by 2

x/2 = 2y/2

1/2x =y

Flip the sides

y = 1/2x

This is of the form y= kx where k = 1/2

x-2y=0 is a direct variation

3 0
3 years ago
CAN YOU PLZZZZZZZZZ HELP ME WITH THIS
satela [25.4K]

\huge\text{Hey there!}

\large\text{Here is your GUIDE for you to go by}\downarrow

\bullet\bold{\  \geq \ or \leq  \ will\ have\ a\ \underline{CLOSED}\ or\ \underline{SHADED\ circle}}\\\bullet\bold{\ >\ or\ \ or

\bold{\ Random\ GUIDE\ \#2}\downarrow

\bold{1. \geq is\ GREATER\ or\ EQUAL\ TO}\\\bold{2. \leq\ is\ LESS\ or\ EQUAL\ TO}\\\bold{3. >\ is\ GREATER\ THAN}\\\bold{4. < \ is\ LESS\ THAN}

“\bold{6>x}”

\bold{Well, based\ on\ your\ GUIDE\ we\ can do\ PROCESS\ OF\ ELIMINATION.}\\\\\bold{REMEMBER: < or > will\ have\ a\ O P E N E D\ circle.\ This\ throws\ A\ \& C}\\\bold{as\ your\ results\ because\ they\ are\ CLOSED\ CIRCLES\ and\ we\ are}\\\bold{looking\ for\ O P E N E D\ circles. This\ leads\ B\ & D\ as\ your\ POSSIBLE}\\\bold{result}

\bold{>\  equals \ GREATER\ THAN}

\bold{Graph\ B.\ is\ SHADED\ to\ the\ LEFT\ which\ we\ need}

\bold{Graph\ D.\ would\ be\ TOO\ BIG}

\boxed{\boxed{\bold{Answer: Option\ B.\ }}}\huge\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite40:)}

4 0
3 years ago
Read 2 more answers
Probability of a standard six side dice landing on a four in the first three rolls?
Illusion [34]

Answer:

91/216

Step-by-step explanation:

The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.

P(at least one 4) = 1 − P(no 4s)

P(at least one 4) = 1 − (5/6)³

P(at least one 4) = 91/216

Alternatively, you can calculate it this way.

The probability of getting a 4 on the first roll is 1/6.

The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.

The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.

The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.

6 0
3 years ago
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