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choli [55]
2 years ago
11

Ratios equivalent to 10:9.

Mathematics
2 answers:
Aleks04 [339]2 years ago
3 0

Answer:20:18

Step-by-step explanation:

Zinaida [17]2 years ago
3 0

Answer:

111. Also, 5:3

Step-by-step explanation:

yw

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Pete's monthly housing budget is $2,250. His monthly costs are $215.75 for insurance, $143.50 for utilities, and $273 for taxes.
kogti [31]
Answer should be b hope it helps
4 0
3 years ago
I have to get this so I pass help plz
pshichka [43]

Answer:

\boxed{\sf x=-2}

\boxed{\sf y=-4}

Step-by-step explanation:

<u>First, Let's  solve for x in -2x+2y=-4:</u>

\sf -2x+2y=-4

<u>Subtract 2y from both sides:</u>

\sf -2x+2y-2y=-4-2y

\sf -2x=-4-2y

<u>Divide both sides by -2:</u>

\sf \cfrac{-2x}{-2}=-\cfrac{4}{-2}-\cfrac{2y}{-2}

\bold{ x=y+2}

<u>Now, we'll substitute x=y+2 to 3x+3y=-18:</u>

\sf 3x+3y=-18

→ let x=2+y

\sf 3\bold{(2+y)}+3y=-18

<u>Simplify:</u>

\sf 6+6y=-18

<u>Now, let's solve for y in 6+6y=-18</u>

\sf 6+6y=-18

<u>Subtract 6 from both sides:</u>

\sf 6+6y-6=-18-6

\sf 6y=-24

<u>Divide both sides by 6:</u>

\sf \cfrac{6y}{6}=\cfrac{-24}{6}

\bold{ y=-4}

<u>Now, substitute y=-4 into x=2+y:</u>

\sf x=2+y

→ let y = -4

\sf x=2+\bold{-4}

\bold{x=-2}

Therefore, x=-2 and y=-4.

<u>_____________________________________</u>

5 0
2 years ago
FREE BRAINLIEST!! ill also answer questions that you have posted if you answer these 2 questions correctly!! ((Answer both quest
Gala2k [10]

Answer:

D and C

Step-by-step explanation:

I don't really know if my answers are even correct but I did some research on them. I don't want to waste your time --or mine.

3 0
3 years ago
Read 2 more answers
PLEASE ANSWERRRRRRRRRR
Jet001 [13]

Step-by-step explanation:

D. Both charges must be different.

Because, like charges repel each other and different charges attract each other.

5 0
3 years ago
Read 2 more answers
Given: ABCD is a ∥-gram, BF ⊥ CD , BE ⊥ AD, Prove: △ABE∼△CBF
drek231 [11]

Answer:

Hence proved △ABE∼△CBF.

Step-by-step explanation:

Given,

ABCD is a parallelogram.

BF ⊥ CD    and

BE ⊥ AD

To Prove : △ABE∼△CBF

We have drawn the diagram for your reference.

Proof:

Since ABCD is a parallelogram,

So according to the property of parallelogram opposite angles are equal in measure.

\therefore m\angle A = m\angle B ⇒1

And given that BF ⊥ CD and BE ⊥ AD.

So we can say that;

m\angle F=m\angle E=90\° ⇒2

Now In △ABE and △CBF

∠A = ∠C   (from 1)

∠E = ∠F    (from 2)

So by A.A. similarity postulate;

△ABE∼△CBF

7 0
3 years ago
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