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777dan777 [17]
3 years ago
10

What assumption must be made about the sun rays if you use this method of determining the circumference of a large sphere?

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
Based on the given details, the assumption that must be made about the sun rays if using the method of determining the circumference of a large sphere is that, the rays it emits are of a certain angle from one another and these rays would travel in parallel. These rays are not touching, therefore, its angles are the same. Hope this answer helps.
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Malcolm wanted to build a dog run with an area of 64. What is the smallest perimeter the dog run could be
Brrunno [24]
The shape with the most area with the smallest perimiter is the circle
first find the radius
then find the circumfernece(permiter)
so
area=64
shape=circle
area of circle=pi times r^2
pi times r^2=64
divide both sides by pi (aprox 3.141592)
r^2=20.3718
square root both sdies
r=4.5

circumference=2pi times r
2 times 3.141592 times 4.5=28.36
perimiter is 28.36
3 0
3 years ago
PLEASE SHOW WORK - HELP FAST
Ksivusya [100]

Answer:

SSS

∆PQR = 43

Step-by-step explanation:

The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.

9 + 6y + 5 + 14 = 9 + 8y +14

28 + 6y = 9 + 8y + 14

28 + 6y = 8y + 23

      -6y    -6y

--------------------------

  28 = 2y + 23

 -23           -23

---------------------

      5 = 2y

     ----   ----

      2      2  

  2.5  =   y

9 + 14 + 6(2.5) + 5

23 + 15 + 5

 23 + 20

     43

∆PQR = 43

4 0
3 years ago
Please give me the answers or at least explain how I’m supposed to do it
mr_godi [17]

when solving sales tax it's pretty simple because all you do is add everything for a subtotal and multiply your sub total by the tax so i'll use the first as an example your subtotal is 19.96 x0.05 to get 0.99 <-- your sales tax and your final total with tax to be 20.96

3 0
3 years ago
Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your
love history [14]

If we substitute x=r\cos\theta and y=r\sin\theta, we get r^2=x^2+y^2, so that

z=\cos(x^2+y^2)=\cos(r^2)

which is independent of \theta, which in turn means the surface can be treated like a surface of revolution.

Consider the function f(t)=\cos(t^2) defined over 0\le t\le1. Revolve the curve C described by f(t) about the line t=0. The area of the surface obtained in this way is then

\displaystyle2\pi\int_C\mathrm dS=2\pi\int_0^1\sqrt{1+f'(t)^2}\,\mathrm dt

=\displaystyle2\pi\int_0^1\sqrt{1+(-2t\sin(t^2))^2}\,\mathrm dt

=\displaystyle2\pi\int_0^1\sqrt{1+4t^2\sin^2(t^2)}\,\mathrm dt\approx7.4144

4 0
3 years ago
PLZZZZZZ HLPPPPP MEEEEEEE how could you find the y coordinate of the midpoint of a vertical line segment with endpoints at (0, 0
emmainna [20.7K]

Answer:

A. Add the endpoints

C. Divide -12 by 2

Step-by-step explanation:

To find the midpoint of the vertical line segment with endpoints (0, 0) and (0, -12).

Step 1: Add the endpoints (y-coordinates)

0+-12=-12

Step 2: Divide -12 by 2

-12/2=-6

Therefore, the y-coordinate of the midpoint of a vertical line segment is -6.

Options A and C are correct.

5 0
3 years ago
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