Answer:
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Mean of the Population (μ) = 281
Standard deviation of the Population = 34.4
Let 'X' be a random variable in Normal distribution
Given X = 290

<u><em>Step(ii):-</em></u>
<em> The probability that the mean test score is greater than 290</em>
P(X⁻ > 290 ) = P( Z > 2.027)
= 0.5 - A ( 2.027)
= 0.5 - 0.4783
= 0.0217
The probability that the mean test score is greater than 290
P(X⁻ > 290 ) = 0.0217
Answer:
It is -0.48
Step-by-step explanation:
I would guess 61 in my school we only do things like this x4 - 5 x times four minus five so I don’t know if that’s right but that would be my guess if that isn’t right it would be 62 times 2