The shape with the most area with the smallest perimiter is the circle
first find the radius
then find the circumfernece(permiter)
so
area=64
shape=circle
area of circle=pi times r^2
pi times r^2=64
divide both sides by pi (aprox 3.141592)
r^2=20.3718
square root both sdies
r=4.5
circumference=2pi times r
2 times 3.141592 times 4.5=28.36
perimiter is 28.36
Answer:
SSS
∆PQR = 43
Step-by-step explanation:
The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.
9 + 6y + 5 + 14 = 9 + 8y +14
28 + 6y = 9 + 8y + 14
28 + 6y = 8y + 23
-6y -6y
--------------------------
28 = 2y + 23
-23 -23
---------------------
5 = 2y
---- ----
2 2
2.5 = y
9 + 14 + 6(2.5) + 5
23 + 15 + 5
23 + 20
43
∆PQR = 43
when solving sales tax it's pretty simple because all you do is add everything for a subtotal and multiply your sub total by the tax so i'll use the first as an example your subtotal is 19.96 x0.05 to get 0.99 <-- your sales tax and your final total with tax to be 20.96
Answer:
A. Add the endpoints
C. Divide -12 by 2
Step-by-step explanation:
To find the midpoint of the vertical line segment with endpoints (0, 0) and (0, -12).
Step 1: Add the endpoints (y-coordinates)
0+-12=-12
Step 2: Divide -12 by 2
-12/2=-6
Therefore, the y-coordinate of the midpoint of a vertical line segment is -6.
Options A and C are correct.