15 is A, 22+X=8
I don't have time to solve the rest RN but will come back later
Answer:
The range is the difference between the biggest and smaller values of a set. The median is the middle value of a set. So we cannot say were the lowest score was found, comparing the median and ranges, because it could be that some repeated value very low or high is biasing the median, we could do it with the mean perhaps. So the proposal is false.
Answer:i think its the first one
Step-by-step explanation:
Nothing else makes sense
Take the vector u = <ux, uy> = <4, 3>.
Find the magnitude of u:
||u|| = sqrt[ (ux)^2 + (uy)^2]
||u|| = sqrt[ 4^2 + 3^2 ]
||u|| = sqrt[ 16 + 9 ]
||u|| = sqrt[ 25 ]
||u|| = 5
To find the unit vector in the direction of u, and also with the same sign, just divide each coordinate of u by ||u||. So the vector you are looking for is
u/||u||
u * (1/||u||)
= <4, 3> * (1/5)
= <4/5, 3/5>
and there it is.
Writing it in component form:
= (4/5) * i + (3/5) * j
I hope this helps. =)
