From the given function modeling the height of the ball:
f(x)=-0.2x^2+1.4x+7
A] The maximum height of the ball will be given by:
At max height f'(x)=0
from f(x),
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
thus the maximum height would be:
f(3.5)=-0.2(3.5)^2+1.4(3.5)+7
f(3.5)=9.45 ft
b]
How far from where the ball was thrown did this occur:
from (a), we see that at maximum height f'(x)=0
f'(x)=-0.4x+1.4
solving for x we get:
-0.4x=-1.4
x=3.5ft
This implies that it occurred 3.5 ft from where the ball was thrown.
c] How far does the ball travel horizontally?
f(x)=-0.2x^2+1.4x+7
evaluationg the expression when f(x)=0 we get:
0=-0.2x^2+1.4x+7
Using quadratic equation formula:
x=-3.37386 or x=10.3739
We leave out the negative and take the positive answer. Hence the answer 10.3739 ft horizontally.
Answer:
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Answer:
see explanation
Step-by-step explanation:
given the endpoints of a line segment
(x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[
(x₁ + x₂), (y₁ + y₂) ]
For example
consider the endpoints (4, 2) and (6, - 4)
midpoint = [(4 + 6), (2 - 4)] = (5, - 1)
Answer:
3/2 or 1 1/2
Step-by-step explanation:
Answer:
6 by 7 feet is 42 square feet that means that the gravel path would have to be 30 feet.
Step-by-step explanation:
6x7=42
42+30=72
