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3 years ago

What is the unit rate of 92 dollars for 2 video games

Mathematics

1 answer:

arsen [322]3 years ago

7 0

Answer:

It is $46 per video game because 92 divided by 2 is 46.

Step-by-step explanation:

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A single die is rolled. Find the probability of rolling and odd number or a number less than 4

sweet [91]

6 sides on a dice 1-6 numbers probability is 4/6 or 2/3

3 0

3 years ago

1) A basket of apples are given to a group of students. If 3 apples are given to each student, there will be 8 apples left. If 5

sattari [20]

Answer:

1) either 5 or 6 students in the group

2) 6 rooms are booked

Step-by-step explanation:

1) x students

3x + 8 = apples

5 (x-1) + y (the one get less than 5 apples)

3x + 8 = 5 (x - 1) + y

3x + 8 = 5x - 5 + y

2x + y = 13

X 1 2 3 4 5 6

Y 11 9 7 5 3 1

because y < 5 so x = 5 or x = 6

2) x rooms are booked

4x + 20 total students

8 (x-1) + y (the students in room not full))

4x + 20 = 8 (x-1) + y

4x + 20 = 8x - 8 + y

4x + y = 28

X 1 2 3 4 5 6

Y 24 20 16 12 8 4

y < 8 answer is 6 rooms

4 0

3 years ago

HELP ASAP!!

mr Goodwill [35]

C I believe hope this is correct :)

3 0

3 years ago

Read 2 more answers

Carl ran around the track 3 more times than Daria and 2 fewer times than Erin. When they were done they added up the number of l

Paul [167]

Answer:

Total laps = 10d

Step-by-step explanation:

Let c = Carl's laps

d = Daria's laps

e = Erin's laps

c = 3d

c = e/2

c + d + e = totals laps

We can insert 3d in place of c in the third equation

3d + d + e = total laps

Also, e/2 equals 3d

e/2 = 3d

Multiply both sides by 2

(e/2 = 3d)2

e = 6d

Insert the new e

3d + d + 6d = 10d = totals laps

3 0

2 years ago

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

6 0

2 years ago

Read 2 more answers