Ok so you round 31 to 30 and 43 to 40 and then you multiply 30 by 40 and get 1200. 1200 is the same thing as 1200.00 bc you can take off the zeros after the decimal and it will be the same. Hope this helped and if your still confused you let me know I'll try to explain it more.
17. RQ is the same as PS.
PS = -1 + 4x
RQ = 3x + 3
-1 + 4x = 3x + 3
4x = 3x + 4
x = 4
Now plug that into RQ.
3(4) + 3 = RQ
15 = RQ
18. Angles G and E are equal to each other.
G = 5x - 9
E = 3x + 11
5x - 9 = 3x + 11
5x = 3x + 20
2x = 20
x = 10
Plug that x into G.
5(10) - 9
41 = G
19. TE and EV are equal to each other.
TE = 4 + 2x
EV = 4x - 4
4 + 2x = 4x - 4
2x = 4x - 8
-2x = -8
x = 4
Plug that into TE.
4 + 2(4)
12 = TE
20. DB and BF are equal.
DB = 5x - 1
BF = 5 + 3x
5x - 1 = 5 + 3x
5x = 6 + 3x
2x = 6
x = 3
Plug that into DB.
5(3) - 1
14 = DB
Step-by-step explanation:
espero te sirva. Hope it helps you
Peanut butter: 8.3 ounces
Sandwich: 5
Divide 8.3 by 5, for equal amount of peanut butter on each sandwich.
8.3/5 = 1.66
She puts 1.66 ounces of peanut butter on each sandwich.
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
