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Murljashka [212]
1 year ago
14

Given the following​ function, find f(−5), f(0), and f(4). f(x)=x2+5

Mathematics
1 answer:
bulgar [2K]1 year ago
6 0

Answer:

30, 5 , 21

Step-by-step explanation:

substitute the values of x into f(x) , then

f(- 5) = (- 5)² + 5 = 25 + 5 = 30

f(0) = 0² + 5 = 0 + 5 = 5

f(4) = 4² + 5 = 16 + 5 = 21

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A pitcher contains 40 fluid ounces of tea Shelby pour 3 cups of tea how many pints are left
Nastasia [14]

Answer:

1 pint of tea left in the pitcher.

Step-by-step explanation:

A pitcher contains 40 fluid ounces

1 cup = 8 fluid ounces

3 cups = 3*8 = 24 fluid ounces

After pouring tea in 3 cups,

tea left in pitcher = 40 - 24 = 16 fluid ounces

1 pint = 16 ounces

Therefore, 1 pint left.

Hope this will helpful.

Thank you.

8 0
2 years ago
Read 2 more answers
Nick made this histogram showing the number of sport caps each of his friends own.
bonufazy [111]
2 or 3 caps = 13
6 or 7 caps = 6
13 - 6 = 7
6 0
3 years ago
Read 2 more answers
Amir says the graph of<br> y= x2 + 16 has -4 as a zero. Is Amir correct?<br> Explain.
sukhopar [10]

Answer:

  • Amir is wrong

Step-by-step explanation:

The function y = x² + 16 is positive for any value of x, hence the graph has no intersection with the x-axis and therefore has no real zero's.

If no zero's, -4 also can't be its zero.

8 0
2 years ago
Read 2 more answers
what algebraic expression must be added to the sum of 3x squared + 4x + 8 and 2x squared -6x + 3 to give 9x squared -2x - 5 as t
gregori [183]
<span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5


</span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 
= 5x^2 - 2x + 11

so

9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 -  5x^2 +  2x - 11
= 4x^2 -16

answer

expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)
3 0
3 years ago
I don’t understand how to do this
schepotkina [342]

Answer:

The solution is x =0.

Step-by-step explanation:

The equation

\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2

can be rewritten as

2* sin(\dfrac{3\pi }{2} +2) =-2

and can be further simplified to

sin(\dfrac{3\pi }{2}+x ) =-1.

Now, taking the inverse sine of both sides we get:

sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)

\bold{(2).}\:  \dfrac{3\pi }{2} +2 =sin^{-1}(-1)

The value of the right side on the interval [0,2\pi) is

sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o) ,

which makes the equation (2)

\dfrac{3\pi }{2}+x  =\dfrac{3\pi}{2}

solving for x gives

\boxed{x = 0}

which is our solution.

4 0
3 years ago
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