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Alinara [238K]
3 years ago
7

Who knows the answer to do this with full work

Mathematics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

Step-by-step explanation:

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Read 2 more answers
X^2+2x-5=0 quadratic form
julsineya [31]

Answer:

-1+√6

-1-√6

Step-by-step explanation:

x²+2x-5=0

x=(-2±√(2²-4(-5)))/2=(-2±√(4+20))/2=(-2±√24)/2

x₁=(-2+√24)/2 or x₂=(-2-√24)/2

x₁=(-2+2√6)/2 or (-2-2√6)/2

x₁=-1+√6 or x₂=-1-√6

3 0
3 years ago
Simplify the following expression using imaginary numbers. Express your answer in a + bi form
mamaluj [8]
<h2>Answer:</h2>

0 - 17i

<h2>Step-by-step explanation:</h2>

Given expression;

i⁸⁰ + i³⁸ - i17

To express the expression in the form a+bi;

<em>i. Rewrite the expression such that it contains terms in i²</em>

(i²)⁴⁰ + (i²)¹⁹ - i17

<em>ii. Solve the result from (i) above using the identity i² = -1</em>

We know that the square root of -1 is i. i.e

\sqrt{-1} = i

<em>Squaring both sides gives</em>

<em>=> </em>(\sqrt{-1} )^{2} = i^{2}<em />

=> -1 = i²

Therefore,

i² = -1

<em>Substitute i² = -1 in step (i) above</em>

(-1)⁴⁰ + (-1)¹⁹ - i17

<em>(iii) Solve the result in (ii)</em>

We know that the when a negative number is raised to the power of an even number, the result is a positive number. If it is raised to the power of an odd number, the result is a negative number. Therefore,

(-1)⁴⁰ + (-1)¹⁹ - i17 becomes

1 + (-1) - i17

0 - i17

<em>(iv) Write the result from (iii) in the form a+bi</em>

0 - 17i

5 0
3 years ago
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