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saw5 [17]
3 years ago
6

A box weighs 5kg. What is the weight of the box in grams?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

5000 grams

Step-by-step explanation:

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Nastasia [14]
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Use the distributive for dx(8+6)
kramer
That would be 14 then.
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What value should go in the red box​
NeX [460]
I’m pretty sure it would be 4, since y= (x) which would be the numbers on the chart and then add 2
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The ratio of blue jays to Robin's was 6 to 7. If there were 84 Robins, how many blue jays were there?​
Paul [167]

Answer:

72

Step-by-step explanation:

<em>Since the ratio of blue jays to robin's was 6 to 7 then if there were 84 robins how many blue jays were there.</em>

<em>6 to 7 can also be express as 6/7</em>

<em>Thus, we can set up a proportion</em>

<em>6/7 = x/84</em>

<em>Now, we have to solve for x</em>

<em>x = 72</em>

<em>Hence, if there were 84 robin there would be 72 blue jays.</em>

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3 0
2 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
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