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3 years ago

A box weighs 5kg. What is the weight of the box in grams?

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

5 0

Answer:

5000 grams

Step-by-step explanation:

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What is the value of ? –4 –2 2 4

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Use the distributive for dx(8+6)

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That would be 14 then.

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2 years ago

What value should go in the red box

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3 years ago

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The ratio of blue jays to Robin's was 6 to 7. If there were 84 Robins, how many blue jays were there?

Paul [167]

Answer:

Step-by-step explanation:

Since the ratio of blue jays to robin's was 6 to 7 then if there were 84 robins how many blue jays were there.

6 to 7 can also be express as 6/7

Thus, we can set up a proportion

6/7 = x/84

Now, we have to solve for x

x = 72

Hence, if there were 84 robin there would be 72 blue jays.

~lenvy~

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2 years ago

What is the largest possible integral value in the domain of the real-valued function

kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

Algebra I

Domain is the set of x-values that can be inputted into function f(x)

Calculus

Antiderivatives
Integral Property: $\int {cf(x)} \, dx = c\int {f(x)} \, dx$
Integration Method: U-Substitution
[Integration] Reverse Power Rule: $\int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C$

Step-by-step explanation:

Step 1: Define

$f(x) = \frac{1}{\sqrt{800-2x} }$

Step 2: Identify Variables

Using U-Substitution, we set variables in order to integrate.

$u = 800-2x\\du = -2dx$

Step 3: Integrate

Define: $\int {f(x)} \, dx$
Substitute: $\int {\frac{1}{\sqrt{800-2x} } } \, dx$
[Integral] Int Property: $-\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx$
[Integral] U-Sub: $-\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du$
[Integral] Rewrite: $-\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du$
[Integral - Evaluate] Reverse Power Rule: $-\frac{1}{2}(2\sqrt{u}) + C$
Simplify: $-\sqrt{u} + C$
Back-Substitute: $-\sqrt{800-2x} + C$
Factor: $-\sqrt{-2(x - 400)} + C$

Step 4: Identify Domain

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

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3 years ago