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2 years ago

11

Using n to represent the cost of an item in dollars before tax and t to represent the amount of sales tax in dollars for that it

em, complete the equation to show the relationship between n and t.
_= 0.085_

1 answer:

love history [14]2 years ago

4 0

Answer:

not sure about the answer

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sweet [91]

2%(random sentence bc I need 20 characters)

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1 year ago

Albert multiplied a whole number by a fraction. The whole number is greater than one. The fraction is greater than zero and less

-BARSIC- [3]

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3 years ago

Find an equation of the line passing through each of the following pairs of points. a (−3, 1), (0, 3)

Svetlanka [38]

$\bf (\stackrel{x_1}{-3}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-3)}}}\implies \cfrac{2}{0+3}\implies \cfrac{2}{3}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{2}{3}}[x-\stackrel{x_1}{(-3)}]\implies y-1=\cfrac{2}{3}(x+3) \\\\\\ y-1=\cfrac{2}{3}x+2\implies y=\cfrac{2}{3}x+3$

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2 years ago

A person takes up 24 inches of space on a stadium bleacher. If one row of bleachers is 150 feet long and there are 20 rows of bl

Feliz [49]

Answer:

1,500 people

Step-by-step explanation:

Remember that

$1\ ft= 12\ in$

Convert ft to in

$150\ ft=150*12=1,800\ in$

<em>Divide the length of a row by the space occupied by one person</em>

$1,800/24=75\ persons$

<em>Multiply by the number of rows to determine the total people that can fit into the stands</em>

$75(20)=1,500\ people$

3 0

3 years ago

Solve for k 5/8(3k+1)-1/4(7k+2)=1

lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

$\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7$

3 0

3 years ago