All categories

3 years ago

CAN SOMEONE PLEASE HELP ME??

Mathematics

2 answers:

EastWind [94]3 years ago

6 0

Answer:

1.) 16.32 x 10^6

2.) 6.6248 x 10^4 (I don't know if this is correct)

Step-by-step explanation:

look at the screenshots below, they'll explain the answers :)

adell [148]3 years ago

3 0

Answer:

1. 1.632*10^7

2. 6.6248*10^-3

Step-by-step explanation:

You might be interested in

It is Jamie’s birthday and her mom just bought her an Xbox. She’s trying to find the surface area of the box so she can determin

Alina [70]

10 times 12 is 120 times 24 equals 2,880 sq2

5 0

3 years ago

Read 2 more answers

How are translations represented as a function

Sedbober [7]

<span>T(x,y) -> (x-3, y+7)
</span><span>is usually i have seen them parametrically defined

</span>

7 0

3 years ago

Help me solve this plssss

weeeeeb [17]

Answer:

UV = 40

UY = 40

Step-by-step explanation:

The sides in YXWVU are the same as the ones in GHIJK times 10.

UV = KJ*10

UY = KG*10

7 0

3 years ago

Read 2 more answers

A=L times W

Dovator [93]

A= 30ft, because you only have to multiply LxW= A that is equal to 2x15=30ft

8 0

3 years ago

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago